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These two nonlinear equations are the power-flow equations for the simple system shown below. fi (x1, x2, u) = 4ux2 sin x₁ +0.6 = 0 f2 (x1, x2, u) = 4x2 - 4ux2 cos x₁ +0.3 = 0 Setting u=1.0 and using the initial estimates of x0) = 0 rad and x₁ one iteration. O 0.3 rad PB1 O -0.150 rad Qg1 O O rad O -0.425 rad 1 IV₁/0° rele ooo j0.25 j6.0 (0) (1) x2 = 1.0, calculate x₁ with just 2 1 |V₂\/82 Pd2 0.6 ૨2 0.3 To load

These two nonlinear equations are the power-flow equations for the simple system shown below. fi (x1, x2, u) = 4ux2 sin x₁ +0.6 = 0 f2 (x1, x2, u) = 4x2 - 4ux2 cos x₁ +0.3 = 0 Setting u=1.0 and using the initial estimates of x0) = 0 rad and x₁ one iteration. O 0.3 rad PB1 O -0.150 rad Qg1 O O rad O -0.425 rad 1 IV₁/0° rele ooo j0.25 j6.0 (0) (1) x2 = 1.0, calculate x₁ with just 2 1 |V₂\/82 Pd2 0.6 ૨2 0.3 To load

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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These two nonlinear equations are the power-flow equations for the simple system shown below. fi (x1, x2, u) = 4ux2 sin x₁ +0.6 = 0 f2 (x1, x2, u) = 4x2 - 4ux2 cos x₁ +0.3 = 0 Setting u=1.0 and using the initial estimates of x0) = 0 rad and x₁ one iteration. O 0.3 rad PB1 O -0.150 rad Qg1 O O rad O -0.425 rad 1 IV₁/0° rele ooo j0.25 j6.0 (0) (1) x2 = 1.0, calculate x₁ with just 2 1 |V₂\/82 Pd2 0.6 ૨2 0.3 To load
Transcribed Image Text:These two nonlinear equations are the power-flow equations for the simple system shown below. fi (x1, x2, u) = 4ux2 sin x₁ +0.6 = 0 f2 (x1, x2, u) = 4x2 - 4ux2 cos x₁ +0.3 = 0 Setting u=1.0 and using the initial estimates of x0) = 0 rad and x₁ one iteration. O 0.3 rad PB1 O -0.150 rad Qg1 O O rad O -0.425 rad 1 IV₁/0° rele ooo j0.25 j6.0 (0) (1) x2 = 1.0, calculate x₁ with just 2 1 |V₂\/82 Pd2 0.6 ૨2 0.3 To load
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