There's a great war between the even and odd numbers. Many numbers already lost their lives in this war and it's your task to end this. You have to determine which group sums larger: the evens, or the odds. The larger group wins. Create a function that takes an array of integers, sums the even and odd numbers separately, then returns the difference between the sum of the even and odd numbers. Examples RUBY war_of_numbers ([2, 8, 7, 5]) → 2 # 2 + 8 = 10 # 7 + 5 = 12 # 12 is larger than 10 # So we return 12 - 10 = 2 war_of_numbers ([12, 90, 75]) -27 war_of_numbers([5, 9, 45, 6, 2, 7, 34, 8, 6, 90, 5, 243]) 168
There's a great war between the even and odd numbers. Many numbers already lost their lives in this war and it's your task to end this. You have to determine which group sums larger: the evens, or the odds. The larger group wins. Create a function that takes an array of integers, sums the even and odd numbers separately, then returns the difference between the sum of the even and odd numbers. Examples RUBY war_of_numbers ([2, 8, 7, 5]) → 2 # 2 + 8 = 10 # 7 + 5 = 12 # 12 is larger than 10 # So we return 12 - 10 = 2 war_of_numbers ([12, 90, 75]) -27 war_of_numbers([5, 9, 45, 6, 2, 7, 34, 8, 6, 90, 5, 243]) 168
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
![There's a great war between the even and odd numbers. Many numbers already lost their
lives in this war and it's your task to end this. You have to determine which group sums
larger: the evens, or the odds. The larger group wins.
Create a function that takes an array of integers, sums the even and odd numbers
separately, then returns the difference between the sum of the even and odd numbers.
Examples
RUBY
war_of_numbers ([2, 8, 7, 5]) → 2
# 2 + 8 = 10
# 7 + 5 = 12
# 12 is larger than 10
# So we return 12 - 10 = 2
war_of_numbers ([12, 90, 75])
war_of_numbers([5, 9, 45, 6, 2, 7, 34, 8, 6, 90, 5, 243])
→ 27
168](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fefc32703-d722-4b37-addd-cc775fbac423%2F131a8a88-cb79-4bc9-9fe4-c0ca611b51e1%2Fixp270d_processed.png&w=3840&q=75)
Transcribed Image Text:There's a great war between the even and odd numbers. Many numbers already lost their
lives in this war and it's your task to end this. You have to determine which group sums
larger: the evens, or the odds. The larger group wins.
Create a function that takes an array of integers, sums the even and odd numbers
separately, then returns the difference between the sum of the even and odd numbers.
Examples
RUBY
war_of_numbers ([2, 8, 7, 5]) → 2
# 2 + 8 = 10
# 7 + 5 = 12
# 12 is larger than 10
# So we return 12 - 10 = 2
war_of_numbers ([12, 90, 75])
war_of_numbers([5, 9, 45, 6, 2, 7, 34, 8, 6, 90, 5, 243])
→ 27
168
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