There were 53 competitors in a downhill skiing event. Their times (in seconds) are a) The mean time was 103.63 seconds, with a standard deviation of 4.04 seconds. shown below. If the normal model is appropriate, what percent of times will be less than 107.67 seconds? 98.14 98.14 98.43 98.69 99.54 84 % 99.62 99.78 100.06 100.29 100.62 (Round to the nearest integer as needed.) 100.76 101.48 101.71 101.76 101.77 b) What is the actual percent of times less than 107.67 seconds? 101.94 101.95 102.11 102.19 102.29 102.37 102.37 102.41 102.75 102.78 (Round to one decimal place as needed.) 102.95 102.98 103.08 103.12 103.24 103.34 103.38 103.43 103.52 103.53 103.78 104.32 104.65 104.78 105.05 105.28 105.29 105.38 105.49 105.61 105.73 105.88 106.89 108.12 109.55 116.17 116.76 117.26

There were 53 competitors in a downhill skiing event. Their times (in seconds) are a) The mean time was 103.63 seconds, with a standard deviation of 4.04 seconds. shown below. If the normal model is appropriate, what percent of times will be less than 107.67 seconds? 98.14 98.14 98.43 98.69 99.54 84 % 99.62 99.78 100.06 100.29 100.62 (Round to the nearest integer as needed.) 100.76 101.48 101.71 101.76 101.77 b) What is the actual percent of times less than 107.67 seconds? 101.94 101.95 102.11 102.19 102.29 102.37 102.37 102.41 102.75 102.78 (Round to one decimal place as needed.) 102.95 102.98 103.08 103.12 103.24 103.34 103.38 103.43 103.52 103.53 103.78 104.32 104.65 104.78 105.05 105.28 105.29 105.38 105.49 105.61 105.73 105.88 106.89 108.12 109.55 116.17 116.76 117.26

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Find the standard deviation of the sample data below: 3,5,6,9 (Answer: 1 decimal place) Type your answer... Previous
In the 1992 presidential election, Alaska's 40 election districts averaged 1993 votes per district for President Clinton. The standard deviation was 584. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X ~ N( b. Is 1993 a population mean or a sample mean? Select an answer v C. Find the probability that a randomly selected district had fewer than 2053 votes for President Clinton. d. Find the probability that a randomly selected district had between 2074 and 2208 votes for President Clinton. e. Find the 95th percentile for votes for President Clinton. Round your answer to the nearest whole number.
A distribution has mean 100 and standard deviation 3. What is the largest percent of the data that is guaranteed to be between 40 and 160 93.75 96 97.44 99.75 99.99
Please see attached.
open file attached for question
The race speeds (in minutes) for the top eight cars in a 200-mile race are listed below. Use the range rule of thumb to estimate the standard deviation. Round results to the nearest tenth.181.0 180.6 189.2 182.2 175.6 180.0 177.9 181.8 Question content area bottomPart 1A.6.8 minutesB.7.5 minutesC.3.4 minutesD.1.1 minutes
In the 1992 presidential election, Alaska's 40 election districts averaged 2038 votes per district for President Clinton. The standard deviation was 576. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.a. What is the distribution of X? X ~ N(,)b. Is 2038 a population mean or a sample mean? Select an answer Population Mean Sample Mean c. Find the probability that a randomly selected district had fewer than 1842 votes for President Clinton. d. Find the probability that a randomly selected district had between 1997 and 2099 votes for President Clinton. e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number.
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean u = $1.506 and standard deviation o = $1.004. Click the icon to view the frequency distribution for the tax rates. Frequency distribution of cigarette tax rates Tax Rate Frequency 0.00–0.49 7 0.50-0.99 14 1.00–1.49 7 1.50–1.99 2.00–2.49 5 2.50–2.99 5 3.00–3.49 3.50–3.99 1 4.00-4.49 1