There is at least one error below. Click on the image where the FIRST error occurs. 3 Let f(x)= = ³. Find f'(1). == x f'(1) = lim h→0 = lim h→0 f(1+h)-f(1) h (² + ³) - ³ h 312 = lim h→0 h

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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There is at least one error below. Click on the image where the FIRST error
occurs.
3
Let f(x)= ==. Find f'(1).
پټ د
Selected Coordinates
Clear
f'(1) = lim
h→0
= lim
h→0
- lim
f(1+h)-f(1)
h
( ²³² 2 + 1 2²/1) - ³²0
h
lim h
h→0 h
= 3
=|-|C
= lim 3
h→0
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Transcribed Image Text:There is at least one error below. Click on the image where the FIRST error occurs. 3 Let f(x)= ==. Find f'(1). پټ د Selected Coordinates Clear f'(1) = lim h→0 = lim h→0 - lim f(1+h)-f(1) h ( ²³² 2 + 1 2²/1) - ³²0 h lim h h→0 h = 3 =|-|C = lim 3 h→0 Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All A
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