There is a Math 338 class with ? = 30 students. Their first exam has a time limit of 80 minutes. Suppose there is a probability ? = 0.90 that any given student finishes their exam in the time allowed. 11.What is the expected number of students that will not finish the exam in the 80 minutes allowed? 12.Multiple Choice: Suppose one student in the class has a probability ? ∗ = 0.99 that they finish the exam in the time allowed. Can we use the same method as the previous question to calculate the expected number of students that will not finish? Yes, because the number of students is still fixed at ? = 30. No, because not all of the students have the same probability of finishing. Yes, because each student can still either finish or not finish on time. No, because students finishing are no longer independent events. 13.Multiple Choice: Suppose the students could work together. Can we use the same method as the previous question to calculate the expected number of students that will not finish? Yes, because the number of students is still fixed at ? = 30. No, because not all of the students have the same probability of finishing. Yes, because each student can still either finish or not finish on time. No, because students finishing are no longer independent events.
There is a Math 338 class with ? = 30 students. Their first exam has a time limit
of 80 minutes. Suppose there is a
finishes their exam in the time allowed.
11.What is the expected number of students that will not finish the exam in the
80 minutes allowed?
12.Multiple Choice: Suppose one student in the class has a probability ?
∗
=
0.99 that they finish the exam in the time allowed. Can we use the same
method as the previous question to calculate the expected number of
students that will not finish?
- Yes, because the number of students is still fixed at ? = 30.
- No, because not all of the students have the same probability of
finishing.
- Yes, because each student can still either finish or not finish on time.
- No, because students finishing are no longer independent
events.
13.Multiple Choice: Suppose the students could work together. Can we use the
same method as the previous question to calculate the expected number of
students that will not finish?
- Yes, because the number of students is still fixed at ? = 30.
- No, because not all of the students have the same probability of
finishing.
- Yes, because each student can still either finish or not finish on time.
- No, because students finishing are no longer independent events.
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