There exists a bounded sequence (un)neN that has a monotone diverging subsequence. a. False, the subsequence is bounded (its values are contained in the values of (un)nЄN) and this, if it is monotone, by MCT it converges. b. False, any monotone sequence converges by the MCT. c. True, here is an example: (un)nɛN = (−1,1, —1, 2, —1, 3, . . . ), which has the monotone diverging sub- sequence (0, 1, 2, 3, ...). d. True, here is an example: (0, 1, 2, 0, 1, 2, 0, 1, 2,...), which has the diverging subsequence (0, 1, 0, 1, ...).

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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There exists a bounded sequence (un)neN that has a monotone diverging subsequence.
a. False, the subsequence is bounded (its values are contained in the values of (un)neN) and this, if it is
monotone, by MCT it converges.
b. False, any monotone sequence converges by the MCT.
c. True, here is an example: (un)neN = (−1, 1, −1, 2,−1, 3, ... ), which has the monotone diverging sub-
sequence (0, 1, 2, 3, … … . ).
d. True, here is an example:
(0, 1, 2, 0, 1, 2, 0, 1, 2, ...), which has the diverging subsequence (0, 1, 0, 1,...).
Transcribed Image Text:There exists a bounded sequence (un)neN that has a monotone diverging subsequence. a. False, the subsequence is bounded (its values are contained in the values of (un)neN) and this, if it is monotone, by MCT it converges. b. False, any monotone sequence converges by the MCT. c. True, here is an example: (un)neN = (−1, 1, −1, 2,−1, 3, ... ), which has the monotone diverging sub- sequence (0, 1, 2, 3, … … . ). d. True, here is an example: (0, 1, 2, 0, 1, 2, 0, 1, 2, ...), which has the diverging subsequence (0, 1, 0, 1,...).
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