There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide water react to form acetylene and calcium hydroxide: CaC₂(s) + 2 H₂O(g) → C₂H₂(g) + Ca(OH)₂(s) AH=-414. kJ In the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6C₂H₂(g) + 3 CO₂(g) + 4H₂O(g) → 5 CH₂CHCO₂H(g) - ΔΗ=132. kJ Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. Round your answer to the nearest kJ. X S
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide water react to form acetylene and calcium hydroxide: CaC₂(s) + 2 H₂O(g) → C₂H₂(g) + Ca(OH)₂(s) AH=-414. kJ In the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6C₂H₂(g) + 3 CO₂(g) + 4H₂O(g) → 5 CH₂CHCO₂H(g) - ΔΗ=132. kJ Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. Round your answer to the nearest kJ. X S
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Chapter1: Chemical Foundations
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![There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide:
\[ \text{CaC}_2(s) + 2 \text{H}_2\text{O}(g) \rightarrow \text{C}_2\text{H}_2(g) + \text{Ca(OH)}_2(s) \quad \Delta H = -414 \, \text{kJ} \]
In the second step, acetylene, carbon dioxide, and water react to form acrylic acid:
\[ 6 \text{C}_2\text{H}_2(g) + 3 \text{CO}_2(g) + 4 \text{H}_2\text{O}(g) \rightarrow 5 \text{CH}_2\text{CHCO}_2\text{H}(g) \quad \Delta H = 132 \, \text{kJ} \]
Calculate the net change in enthalpy for the formation of **one mole** of acrylic acid from calcium carbide, water, and carbon dioxide from these reactions. Round your answer to the nearest kJ.
\[ \text{Box for Answer:} \, \Box \, \text{kJ} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fad08dc2d-a8b1-4577-bbd3-fa0bc9778c94%2F8bb12cd0-b0cf-4768-8965-0d3c7103d41d%2Fzwe7j3j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide:
\[ \text{CaC}_2(s) + 2 \text{H}_2\text{O}(g) \rightarrow \text{C}_2\text{H}_2(g) + \text{Ca(OH)}_2(s) \quad \Delta H = -414 \, \text{kJ} \]
In the second step, acetylene, carbon dioxide, and water react to form acrylic acid:
\[ 6 \text{C}_2\text{H}_2(g) + 3 \text{CO}_2(g) + 4 \text{H}_2\text{O}(g) \rightarrow 5 \text{CH}_2\text{CHCO}_2\text{H}(g) \quad \Delta H = 132 \, \text{kJ} \]
Calculate the net change in enthalpy for the formation of **one mole** of acrylic acid from calcium carbide, water, and carbon dioxide from these reactions. Round your answer to the nearest kJ.
\[ \text{Box for Answer:} \, \Box \, \text{kJ} \]
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![**Transcription for Educational Website**
**Topic: Industrial Preparation of Acrylic Acid**
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics.
**Step 1: Formation of Acetylene**
In the first step, calcium carbide and water react to form acetylene and calcium hydroxide:
\[ \text{CaC}_2(s) + 2 \text{H}_2\text{O}(g) \rightarrow \text{C}_2\text{H}_2(g) + \text{Ca(OH)}_2(s) \quad \Delta H = -414 \, \text{kJ} \]
**Step 2: Formation of Acrylic Acid**
In the second step, acetylene, carbon dioxide, and water react to form acrylic acid:
\[ 6 \text{C}_2\text{H}_2(g) + 3 \text{CO}_2(g) + 4 \text{H}_2\text{O}(g) \rightarrow 5 \text{CH}_2\text{CHCO}_2\text{H}(g) \quad \Delta H = 132 \, \text{kJ} \]
**Calculation Task:**
Calculate the net change in enthalpy for the formation of *one mole* of acrylic acid from calcium carbide, water, and carbon dioxide from the above reactions. Round your answer to the nearest kJ.
**Student Answer:**
The calculated net change in enthalpy is: \(-392 \, \text{kJ}\)](https://content.bartleby.com/qna-images/question/ad08dc2d-a8b1-4577-bbd3-fa0bc9778c94/f110031b-736c-4607-9ee1-5a6984c5c249/1htz6h_processed.jpeg)
Transcribed Image Text:**Transcription for Educational Website**
**Topic: Industrial Preparation of Acrylic Acid**
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics.
**Step 1: Formation of Acetylene**
In the first step, calcium carbide and water react to form acetylene and calcium hydroxide:
\[ \text{CaC}_2(s) + 2 \text{H}_2\text{O}(g) \rightarrow \text{C}_2\text{H}_2(g) + \text{Ca(OH)}_2(s) \quad \Delta H = -414 \, \text{kJ} \]
**Step 2: Formation of Acrylic Acid**
In the second step, acetylene, carbon dioxide, and water react to form acrylic acid:
\[ 6 \text{C}_2\text{H}_2(g) + 3 \text{CO}_2(g) + 4 \text{H}_2\text{O}(g) \rightarrow 5 \text{CH}_2\text{CHCO}_2\text{H}(g) \quad \Delta H = 132 \, \text{kJ} \]
**Calculation Task:**
Calculate the net change in enthalpy for the formation of *one mole* of acrylic acid from calcium carbide, water, and carbon dioxide from the above reactions. Round your answer to the nearest kJ.
**Student Answer:**
The calculated net change in enthalpy is: \(-392 \, \text{kJ}\)
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