There are two forces on the 2.13 kg box in the overhead view of the figure but only one is shown. For F₁ = 28.9 N, a = 14.0 m/s², and 8 = 30.5°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.) (a) Number i (b) Number MI (c) Number i i+ Units Units MI X j Units

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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The image presents a physics problem involving two forces acting on a 2.13 kg box. The problem includes finding the second force. Given:

- \( F_1 = 28.9 \, \text{N} \)
- \( a = 14.0 \, \text{m/s}^2 \)
- \( \theta = 30.5^\circ \)

Tasks:

1. **Find the second force (a) in unit-vector notation.**
   - Complete the boxes for the components "i" and "j" with the appropriate units.

2. **Find the magnitude of the second force (b).**
   - Enter the number and select the correct units.

3. **Determine the direction of the second force (c).**
   - Enter the angle as a negative value measured from the +x direction with the appropriate units.

Diagram Explanation:

- The diagram shows a rectangle representing the box with an overhead view.
- The x and y axes intersect at the rectangle’s center.
- The force \( \vec{F}_1 \) is shown along the positive x direction.
- The acceleration vector \( \vec{a} \) is drawn at an angle \( \theta \) with the x-axis, pointing diagonally into the quadrant below the positive x-axis.
Transcribed Image Text:The image presents a physics problem involving two forces acting on a 2.13 kg box. The problem includes finding the second force. Given: - \( F_1 = 28.9 \, \text{N} \) - \( a = 14.0 \, \text{m/s}^2 \) - \( \theta = 30.5^\circ \) Tasks: 1. **Find the second force (a) in unit-vector notation.** - Complete the boxes for the components "i" and "j" with the appropriate units. 2. **Find the magnitude of the second force (b).** - Enter the number and select the correct units. 3. **Determine the direction of the second force (c).** - Enter the angle as a negative value measured from the +x direction with the appropriate units. Diagram Explanation: - The diagram shows a rectangle representing the box with an overhead view. - The x and y axes intersect at the rectangle’s center. - The force \( \vec{F}_1 \) is shown along the positive x direction. - The acceleration vector \( \vec{a} \) is drawn at an angle \( \theta \) with the x-axis, pointing diagonally into the quadrant below the positive x-axis.
Expert Solution
Step 1

Calculate the magnitude of the net force.

F=maF=(2.13 kg)(14 m/s2)F=29.82 N

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