There are three identical yellow books, two identical black books, and four identical orange books. How many different patterns are possible if the books are arranged on a shelf? [A] 24 [B] 362,880 [C] 9 [D] 1260

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter9: Sequences, Probability And Counting Theory
Section9.5: Counting Principles
Problem 46SE: How many ways can a committee of 3 freshmen and 4 juniors be formed from a group of 8 freshmen and...
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Please solve questions 3 and 5.

 

 

**Problem on Counting Arrangements of Identical Items**

In this combinatorial problem, there are three identical yellow books, two identical black books, and four identical orange books. The goal is to determine how many different patterns are possible if these books are arranged on a shelf.

**Question:**
How many different patterns are possible if the books are arranged on a shelf?

**Options:**
- [A] 24
- [B] 362,880
- [C] 9
- [D] 1260

**Solution Explanation:**
This problem is related to counting permutations of multiset. The formula to find the number of different arrangements (patterns) when there are groups of identical items is:

\[ \frac{n!}{n_1! \cdot n_2! \cdot n_3! \cdots} \]

Here, \(n\) is the total number of items, and \(n_1, n_2, n_3\), etc., are the counts of each type of identical items.

In our problem:
- Total number of books \(n = 3 + 2 + 4 = 9\)
- Number of yellow books \(n_1 = 3\)
- Number of black books \(n_2 = 2\)
- Number of orange books \(n_3 = 4\)

Plugging these values into the formula:

\[ \frac{9!}{3! \cdot 2! \cdot 4!} \]

Calculating the factorials:
- \(9! = 362880\)
- \(3! = 6\)
- \(2! = 2\)
- \(4! = 24\)

So,

\[ \frac{362880}{6 \cdot 2 \cdot 24} = \frac{362880}{288} = 1260 \]

Thus, the correct answer is:
- [D] 1260
Transcribed Image Text:**Problem on Counting Arrangements of Identical Items** In this combinatorial problem, there are three identical yellow books, two identical black books, and four identical orange books. The goal is to determine how many different patterns are possible if these books are arranged on a shelf. **Question:** How many different patterns are possible if the books are arranged on a shelf? **Options:** - [A] 24 - [B] 362,880 - [C] 9 - [D] 1260 **Solution Explanation:** This problem is related to counting permutations of multiset. The formula to find the number of different arrangements (patterns) when there are groups of identical items is: \[ \frac{n!}{n_1! \cdot n_2! \cdot n_3! \cdots} \] Here, \(n\) is the total number of items, and \(n_1, n_2, n_3\), etc., are the counts of each type of identical items. In our problem: - Total number of books \(n = 3 + 2 + 4 = 9\) - Number of yellow books \(n_1 = 3\) - Number of black books \(n_2 = 2\) - Number of orange books \(n_3 = 4\) Plugging these values into the formula: \[ \frac{9!}{3! \cdot 2! \cdot 4!} \] Calculating the factorials: - \(9! = 362880\) - \(3! = 6\) - \(2! = 2\) - \(4! = 24\) So, \[ \frac{362880}{6 \cdot 2 \cdot 24} = \frac{362880}{288} = 1260 \] Thus, the correct answer is: - [D] 1260
**Finding the Equation of the Perpendicular Bisector**

The question requires us to find the equation of the perpendicular bisector of the line segment connecting the points \((0, 2)\) and \((-6, -8)\).

Options are provided as follows:

**[A]** \[
y = \frac{3}{5}x - \frac{6}{5}
\]

**[B]** \[
y = -\frac{3}{5}x - \frac{24}{5}
\]

**[C]** \[
y = \frac{3}{5}x + 2
\]

**[D]** \[
y = -\frac{3}{5}x + 2
\]

### Steps to Solve:

1. **Find the midpoint** of the segment connecting \((0, 2)\) and \((-6, -8)\):

   \[
   \left( \frac{0 + (-6)}{2}, \frac{2 + (-8)}{2} \right) = \left( \frac{-6}{2}, \frac{-6}{2} \right) = (-3, -3)
   \]

2. **Determine the slope** of the line segment:

   \[
   \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-8 - 2}{-6 - 0} = \frac{-10}{-6} = \frac{5}{3}
   \]

3. **Find the slope of the perpendicular bisector** (negative reciprocal of the original slope):

   \[
   \text{perpendicular slope} = -\frac{3}{5}
   \]

4. **Use the point-slope form of the equation** of a line with the midpoint \((-3, -3)\) and slope \(-\frac{3}{5}\):

   \[
   y - y_1 = m(x - x_1)
   \]

   \[
   y - (-3) = -\frac{3}{5}(x - (-3))
   \]

   Simplify the equation above to match one of the given options.

5. **Match the simplified equation** to one of the provided choices to find the correct answer.

This will help determine which of the provided options (
Transcribed Image Text:**Finding the Equation of the Perpendicular Bisector** The question requires us to find the equation of the perpendicular bisector of the line segment connecting the points \((0, 2)\) and \((-6, -8)\). Options are provided as follows: **[A]** \[ y = \frac{3}{5}x - \frac{6}{5} \] **[B]** \[ y = -\frac{3}{5}x - \frac{24}{5} \] **[C]** \[ y = \frac{3}{5}x + 2 \] **[D]** \[ y = -\frac{3}{5}x + 2 \] ### Steps to Solve: 1. **Find the midpoint** of the segment connecting \((0, 2)\) and \((-6, -8)\): \[ \left( \frac{0 + (-6)}{2}, \frac{2 + (-8)}{2} \right) = \left( \frac{-6}{2}, \frac{-6}{2} \right) = (-3, -3) \] 2. **Determine the slope** of the line segment: \[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-8 - 2}{-6 - 0} = \frac{-10}{-6} = \frac{5}{3} \] 3. **Find the slope of the perpendicular bisector** (negative reciprocal of the original slope): \[ \text{perpendicular slope} = -\frac{3}{5} \] 4. **Use the point-slope form of the equation** of a line with the midpoint \((-3, -3)\) and slope \(-\frac{3}{5}\): \[ y - y_1 = m(x - x_1) \] \[ y - (-3) = -\frac{3}{5}(x - (-3)) \] Simplify the equation above to match one of the given options. 5. **Match the simplified equation** to one of the provided choices to find the correct answer. This will help determine which of the provided options (
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