There are three closed box labeled with A,B,C. And only one of them with one concert ticket. Now you choose A as your box, then you friend open B and find it is empty. Then you have chance to stick A or switch C. Which probability is larger stick or switch? Now we can denote open B be one event OB. Would you like to explain why P(OB /A)=1/2, and P(OB/C)=1, Thanks

There are three closed box labeled with A,B,C. And only one of them with one concert ticket. Now you choose A as your box, then you friend open B and find it is empty. Then you have chance to stick A or switch C. Which probability is larger stick or switch? Now we can denote open B be one event OB. Would you like to explain why P(OB /A)=1/2, and P(OB/C)=1, Thanks

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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