There are ten female board members and twenty male board members. How many ways are there to make a committee of ten board members? ways How many ways are there to make a committee of ten board members if exactly three must be female? ways Determine the probability of selecting a committee of ten board members where exactly three of the members were female. Write your answer as a decimal, rounded to the nearest thousandth. Answer:

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**Educational Website Content: Combinatorics and Probability**

**Problem Statement:**

There are ten female board members and twenty male board members. 

1. How many ways are there to make a committee of ten board members?

   - [ ] ways

2. How many ways are there to make a committee of ten board members if exactly three must be female?

   - [ ] ways

3. Determine the *probability* of selecting a committee of ten board members where exactly three of the members were female. Write your answer as a decimal, rounded to the nearest thousandth.

   - Answer: [ ]

**Explanation:**

This problem involves calculating the number of combinations in selecting a committee and finding the probability of a specific configuration. 

- **Total Ways to Select Committee:** Here, you'll calculate from a pool of 30 total members (10 females + 20 males).
- **Ways to Select with Conditions:** Specify the number of combinations ensuring exactly three are female.
- **Probability Calculation:** Use the ratio of the favorable outcomes (from condition 2) to the total outcomes (condition 1) to find this probability.

For computations, consider using the combination formula:

\[ C(n, r) = \frac{n!}{r!(n-r)!} \]

where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose.

**Instructions:**

- Fill in the blanks by calculating the appropriate values using the combination formula.
- Ensure your final probability answer is a decimal rounded to the nearest thousandth.

This exercise helps solidify understanding of basic combinatorics and introduces probability-based event calculation in a practical scenario.
Transcribed Image Text:**Educational Website Content: Combinatorics and Probability** **Problem Statement:** There are ten female board members and twenty male board members. 1. How many ways are there to make a committee of ten board members? - [ ] ways 2. How many ways are there to make a committee of ten board members if exactly three must be female? - [ ] ways 3. Determine the *probability* of selecting a committee of ten board members where exactly three of the members were female. Write your answer as a decimal, rounded to the nearest thousandth. - Answer: [ ] **Explanation:** This problem involves calculating the number of combinations in selecting a committee and finding the probability of a specific configuration. - **Total Ways to Select Committee:** Here, you'll calculate from a pool of 30 total members (10 females + 20 males). - **Ways to Select with Conditions:** Specify the number of combinations ensuring exactly three are female. - **Probability Calculation:** Use the ratio of the favorable outcomes (from condition 2) to the total outcomes (condition 1) to find this probability. For computations, consider using the combination formula: \[ C(n, r) = \frac{n!}{r!(n-r)!} \] where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose. **Instructions:** - Fill in the blanks by calculating the appropriate values using the combination formula. - Ensure your final probability answer is a decimal rounded to the nearest thousandth. This exercise helps solidify understanding of basic combinatorics and introduces probability-based event calculation in a practical scenario.
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