### Understanding Atomic StructureIn this exercise, we are given the isotope \( _{7}^{14} \text{HS}^{+5} \). **Problem Statement:**Fill in the blanks in the statement below:"There are ____ protons, ____ neutrons, and ____ electrons in \( _{7}^{14} \text{HS}^{+5} \)."**Explanation:**1. **Protons**: The number of protons is determined by the atomic number, which is the subscript (7 in this case).2. **Neutrons**: The number of neutrons is calculated by subtracting the atomic number (7) from the mass number (14).\[ \text{Number of neutrons} = 14 - 7 = 7 \]3. **Electrons**: For a neutral atom, the number of electrons equals the number of protons. However, here we have a \( +5 \) charge, which indicates the atom has lost 5 electrons.\[ \text{Number of electrons} = 7 - 5 = 2 \]**Solution:**There are **7 protons**, **7 neutrons**, and **2 electrons** in \( _{7}^{14} \text{HS}^{+5} \).

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There are protons, neutrons, and electrons in 147₁ Hs+5

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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An atom is the smallest unit of an element that possesses all the properties of that particular element. Molecules are the smallest unit of a substance that possess all the properties of that particular substance.

Question

### Understanding Atomic Structure

In this exercise, we are given the isotope \( _{7}^{14} \text{HS}^{+5} \).

**Problem Statement:**
Fill in the blanks in the statement below:

"There are ____ protons, ____ neutrons, and ____ electrons in \( _{7}^{14} \text{HS}^{+5} \)."

**Explanation:**
1. **Protons**: The number of protons is determined by the atomic number, which is the subscript (7 in this case).

2. **Neutrons**: The number of neutrons is calculated by subtracting the atomic number (7) from the mass number (14).
\[ \text{Number of neutrons} = 14 - 7 = 7 \]

3. **Electrons**: For a neutral atom, the number of electrons equals the number of protons. However, here we have a \( +5 \) charge, which indicates the atom has lost 5 electrons.
\[ \text{Number of electrons} = 7 - 5 = 2 \]

**Solution:**
There are **7 protons**, **7 neutrons**, and **2 electrons** in \( _{7}^{14} \text{HS}^{+5} \).

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