Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter4: The Structure Of The Atom
Section: Chapter Questions
Problem 42A: Label the subatomic particles shown in Figure 4.22.
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Question
![### Understanding Atomic Structure
In this exercise, we are given the isotope \( _{7}^{14} \text{HS}^{+5} \).
**Problem Statement:**
Fill in the blanks in the statement below:
"There are ____ protons, ____ neutrons, and ____ electrons in \( _{7}^{14} \text{HS}^{+5} \)."
**Explanation:**
1. **Protons**: The number of protons is determined by the atomic number, which is the subscript (7 in this case).
2. **Neutrons**: The number of neutrons is calculated by subtracting the atomic number (7) from the mass number (14).
\[ \text{Number of neutrons} = 14 - 7 = 7 \]
3. **Electrons**: For a neutral atom, the number of electrons equals the number of protons. However, here we have a \( +5 \) charge, which indicates the atom has lost 5 electrons.
\[ \text{Number of electrons} = 7 - 5 = 2 \]
**Solution:**
There are **7 protons**, **7 neutrons**, and **2 electrons** in \( _{7}^{14} \text{HS}^{+5} \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3595772e-86c0-4c31-a854-eeb2464bab68%2Fab6c8df0-2df5-46de-bd5f-653fdb641d26%2F9s0rvtd_processed.png&w=3840&q=75)
Transcribed Image Text:### Understanding Atomic Structure
In this exercise, we are given the isotope \( _{7}^{14} \text{HS}^{+5} \).
**Problem Statement:**
Fill in the blanks in the statement below:
"There are ____ protons, ____ neutrons, and ____ electrons in \( _{7}^{14} \text{HS}^{+5} \)."
**Explanation:**
1. **Protons**: The number of protons is determined by the atomic number, which is the subscript (7 in this case).
2. **Neutrons**: The number of neutrons is calculated by subtracting the atomic number (7) from the mass number (14).
\[ \text{Number of neutrons} = 14 - 7 = 7 \]
3. **Electrons**: For a neutral atom, the number of electrons equals the number of protons. However, here we have a \( +5 \) charge, which indicates the atom has lost 5 electrons.
\[ \text{Number of electrons} = 7 - 5 = 2 \]
**Solution:**
There are **7 protons**, **7 neutrons**, and **2 electrons** in \( _{7}^{14} \text{HS}^{+5} \).
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