there are no pairs of consecutive integers in the winning combination (i1,..., ir) if and only if (j1, ..., jk) has no repeats. The total number of winning combinations is In part k (c), we computed the number of winning combinations with no repeats among (j1,... , jk) to be n - k+1 So, the probability of no consecutive integers is
there are no pairs of consecutive integers in the winning combination (i1,..., ir) if and only if (j1, ..., jk) has no repeats. The total number of winning combinations is In part k (c), we computed the number of winning combinations with no repeats among (j1,... , jk) to be n - k+1 So, the probability of no consecutive integers is
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.7: Probability
Problem 40E: Assume that the probability that an airplane engine will fail during a torture test is 12and that...
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Question
![there are no pairs of consecutive integers in the winning combination (i1,..., ix) if
and only if (j1, ..., jk) has no repeats. The total number of winning combinations is
In part
k
(c), we computed the number of winning combinations with no repeats among (j1,.. ,jk) to be
n – k+1
So, the probability of no consecutive integers is
k](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8b0050e1-8a86-497b-9cc6-b844a5887701%2Fd40593ea-cf39-41ec-8445-9faea08b7c30%2Fq22nf57_processed.jpeg&w=3840&q=75)
Transcribed Image Text:there are no pairs of consecutive integers in the winning combination (i1,..., ix) if
and only if (j1, ..., jk) has no repeats. The total number of winning combinations is
In part
k
(c), we computed the number of winning combinations with no repeats among (j1,.. ,jk) to be
n – k+1
So, the probability of no consecutive integers is
k
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