There are hundreds of apples on the trees, so you randomly choose just 59 apples and get a mean weight of 81.47 grams with a standard deviation of 4.08 grams. Assuming that the weight of the apples is normally distributed, what is the standard error of the 90% confidence interval for the mean weight of the apples. Note: Round your answers to 4 decimal places.
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- It takes an average of 8.1 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will decline if the patient is immediately told the truth about the injury. The EMT randomly selected 62 injured patients to immediately tell the truth about the injury and noticed that they averaged 7.8 minutes for their blood to begin clotting after their injury. Their standard deviation was 2.11 minutes. What can be concluded at the the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? V Select an answer Hj: ? VSelect an answer V c. The test statistic ? V = (please show your answer to 3 decimal places.) d. The p-value = e. The p-value is ? Va f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... (Please show your answer to 4 decimal places.) | the null hypothesis. O The data suggest the population mean is not significantly less than 8.1 at a = 0.05, so…The manager at UPS feels that the weights of packages shipped recently are less than in he past. Records show that in the past packages have had a population mean weight of 36.7 pounds and a population standard deviation of 14.2 pounds. A random sample of last month's shipping records yielded a sample mean weight of 32.1 pounds for 64 packages. Does this indicate that the weights of packages recently shipped is less than 36.7 pounds? Use a = 0.01. Use the Classical Approach.Assume that adults have iq scores that are normally distributed with a mean of 97.9 and a standard deviation 16. Find the first quartile Q1, what is the iq score separating the bottom 25% from the top 75%.
- Suppose you received a score of 95 out of 100on exam 11 . The mean was 79and the standard deviation was 8 . If your score on exam 2 is 90out of 100, and the mean was 60with a standard deviation of 15, then you did:Assume that adults have IQ scores that are normally distributed with a mean of 100.7 and a standard deviation 18.9. Find the first quartile, which is the IQ score separating the bottom 25% from the top to 75%It takes an average of 9.1 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will decline if the patient is immediately told the truth about the injury. The EMT randomly selected 49 injured patients to immediately tell the truth about the injury and noticed that they averaged 8 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.31 minutes. What can be concluded at the the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Hint: Ho: ? H₁: ? Select an answer Select an answer C c. The test statistic? is -2.326. Enter it here d. The p-value is 0.0121364015. Enter it here e. The p-value is ? a f. Based on this, we should Select an answer the null hypothesis. g. Thus, the final conclusion is that ... (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) The data suggest the populaton mean is…
- It takes an average of 12.8 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 51 injured patients to immediately tell the truth about the injury and noticed that they averaged 14.1 minutes for their blood to begin clotting after their injury. Their standard deviation was 4.48 minutes. What can be concluded at the the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? v Select an answer V Hj: ? v Select an answer V c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton mean is significantly different from 12.8 at a =…It takes an average of 10.2 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will decline if the patient is immediately told the truth about the injury. The EMT randomly selected 60 injured patients to immediately tell the truth about the injury and noticed that they averaged 10.1 minutes for their blood to begin clotting after their injury. Their standard deviation was 1.62 minutes. What can be concluded at the the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and altemative hypotheses would be: Họ: Select an answer H1: ? Select an answer c. The test statistic (please show your answer to 3 decimal places.) d. The p-value = e. The p-value is (? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that .. (Please show your answer to 4 decimal places.) O The data suggest the population mean is not significantly less than 10.2 at a = 0.01, so there is…Loretta, who turns 91 this year, has heard that the mean systolic blood pressure among the elderly is 120 millimeters of mercury (mm Hg), but she believes that the actual value is higher. She bases her belief on a recently reported study of 19 randomly selected, elderly adults. The sample mean systolic blood pressure of the adults in the study was 121 mm Hg , and the sample standard deviation was 20 mm Hg. Assume that the population of systolic blood pressures of elderly adults is normally distributed. Based on the study, at the 0.1 level of significance, can it be concluded that μ , the mean systolic blood pressure among elderly adults, is greater than 120 mm Hg? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (a) State the null hypothesis H0? and the alternative hypothesis H1? . H0:? H1:? (b) Determine the type of test statistic to…
- Pyramid Lake is on the Paiute Indian Reservation in Nevada. The lake is famous for cutthroat trout. Suppose a friend tells you that the average length of trout caught in Pyramid Lake isμ=19 inches. However, a survey reported that of a simple random sample of 38 fish caught, the mean length was 19.9 inches, with estimated standard deviation of 3.1 inches. Do these data indicate that the average length of a trout caught in Pyramid Lake is different from μ=19inches? Use α=0.001. What is the value of the test statistic? (Round your answer to two decimal places.)Find the P-value. (Round your answer to four decimal places.)A research scientist wants to know how many times per hour a certain strand of bacteria reproduces. The mean is found to be 7.8 reproductions and the population standard deviation is known to be 2.2 If a sample of 697 was used for the study, construct the 85% confidence interval for the true mean number of reproductions per hour for the bacteria. Round your answers to one decimal placeIt takes an average of 10.4 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 67 injured patients to immediately tell the truth about the injury and noticed that they averaged 10.8 minutes for their blood to begin clotting after their injury. Their standard deviation was 2.94 minutes. What can be concluded at the the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: 10.4 H1: 1.5 c. The test statistic t 1.114 (please show your answer to 3 decimal places.) d. The p-value = 0.0500 (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should accept g. Thus, the final conclusion is that ... v the null hypothesis. O The data suggest that the population mean is not significantly greater than 10.4 at a = 0.05, so there is statistically…
