There are 35 ways of dividing the group into the two teams. As in Exercise 11, the number of ways 10 33 of choosing the 10 players for the first team so as to include both A and B is 8 The number of vays of choosing the 10 players for this team so as not to include either A or B (A and B will then be (33)
There are 35 ways of dividing the group into the two teams. As in Exercise 11, the number of ways 10 33 of choosing the 10 players for the first team so as to include both A and B is 8 The number of vays of choosing the 10 players for this team so as not to include either A or B (A and B will then be (33)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
Related questions
Question
Transcribed Image Text:35
ways of dividing the group into the two teams. As in Exercise 11, the number of ways
There are
10
(33
of choosing the 10 players for the first team so as to include both A and B is
8
The number of
ways of choosing the 10 players for this team so as not to include either A or B (A and B will then be
33
together on the other team) is (). The probability we want is then
10
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
Recommended textbooks for you
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON