There are 3 strategies to solve the turbulent flows in conduits, which are follows: goal given - find h, -L, D and Q Case 1 Case 2 goal given find Q - h, L and D - find D - Q, L and h, Case 3 goal given For cases 2 and 3, there are direct equations available as follows: For Case 2 iterative approach can be avoided sometimes by using eq as: k, 1.78v V&h, I L log 3.7D Q =-2.22D²5 Vgh, IL For Case 3 0יר 32 iterative approach can also be eliminated sometimes (L0 gh, D= ( gh, by using eg as: Select the most appropriate statement. O If hy is not available, you need to assume hf and then solve those equations for Q and D. Once you obtained Q and D, you need to check whether that Q and D are correctly assumed or not, if not you need to re-assume hf until the solution converged. O If h, is available, you can solve those equations for Q and D directly. O All the statements are correct. O For Case 1, we can get h; directly from Darch-Weishbach eq.
There are 3 strategies to solve the turbulent flows in conduits, which are follows: goal given - find h, -L, D and Q Case 1 Case 2 goal given find Q - h, L and D - find D - Q, L and h, Case 3 goal given For cases 2 and 3, there are direct equations available as follows: For Case 2 iterative approach can be avoided sometimes by using eq as: k, 1.78v V&h, I L log 3.7D Q =-2.22D²5 Vgh, IL For Case 3 0יר 32 iterative approach can also be eliminated sometimes (L0 gh, D= ( gh, by using eg as: Select the most appropriate statement. O If hy is not available, you need to assume hf and then solve those equations for Q and D. Once you obtained Q and D, you need to check whether that Q and D are correctly assumed or not, if not you need to re-assume hf until the solution converged. O If h, is available, you can solve those equations for Q and D directly. O All the statements are correct. O For Case 1, we can get h; directly from Darch-Weishbach eq.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![There are 3 strategies to solve the turbulent flows in conduits, which are as follows:
goal
given
- find h,
- L, D and Q
Case 1
Case 2
goal
given
- find Q
- h, L and D
Case 3
- find D
goal
given
- Q, L and h,
For cases 2 and 3, there are direct equations available as follows:
For Case 2
iterative approach can be
avoided sometimes by
1.78V
Q =-2.22D² gh, I L log
3.7D D gh, I L
using eq as:
For Case 3
iterative approach can also
be eliminated sometimes
by using eq as:
12 704
D= 0.66 k!
gh,
gh,
Select the most appropriate statement.
O If h; is not available, you need to assume h and then solve those equations for Q and D. Once you obtained Q and D, you need to check whether that
Q and D are correctly assumed or not, if not you need to re-assume h; until the solution converged.
O If h; is available, you can solve those equations for Q and D directly.
O All the statements are correct.
O For Case 1, we can get h; directly from Darch-Weishbach eq.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F30adc983-743b-4dbc-a506-24761f416b0c%2F2e748867-0717-4575-aad0-2f4fd53cf9d1%2Fbsdm2z9_processed.png&w=3840&q=75)
Transcribed Image Text:There are 3 strategies to solve the turbulent flows in conduits, which are as follows:
goal
given
- find h,
- L, D and Q
Case 1
Case 2
goal
given
- find Q
- h, L and D
Case 3
- find D
goal
given
- Q, L and h,
For cases 2 and 3, there are direct equations available as follows:
For Case 2
iterative approach can be
avoided sometimes by
1.78V
Q =-2.22D² gh, I L log
3.7D D gh, I L
using eq as:
For Case 3
iterative approach can also
be eliminated sometimes
by using eq as:
12 704
D= 0.66 k!
gh,
gh,
Select the most appropriate statement.
O If h; is not available, you need to assume h and then solve those equations for Q and D. Once you obtained Q and D, you need to check whether that
Q and D are correctly assumed or not, if not you need to re-assume h; until the solution converged.
O If h; is available, you can solve those equations for Q and D directly.
O All the statements are correct.
O For Case 1, we can get h; directly from Darch-Weishbach eq.
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