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Theorem: Quotient Rule If f(x) = T(x) B(x) is the quotient of differentiable functions, then f'(x) = B(x)T'(x)+T(x)B'(x) [B(x)]² B'(x)T(x) – T'(x)B(x) f'(x)= = [B(x)]2 B(x)T'(x)T(x)B'(x) f'(x) = = [B'(x)]2 T'(x) f'(x) = B'(x) О f'(x) = B(x)T'(x)T(x)B'(x) [B(x)]2 B'(x)T'(x) T'(x)B'(x) f'(x): = [B'(x)]2

Theorem: Quotient Rule If f(x) = T(x) B(x) is the quotient of differentiable functions, then f'(x) = B(x)T'(x)+T(x)B'(x) [B(x)]² B'(x)T(x) – T'(x)B(x) f'(x)= = [B(x)]2 B(x)T'(x)T(x)B'(x) f'(x) = = [B'(x)]2 T'(x) f'(x) = B'(x) О f'(x) = B(x)T'(x)T(x)B'(x) [B(x)]2 B'(x)T'(x) T'(x)B'(x) f'(x): = [B'(x)]2

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Theorem: Quotient Rule If f(x) = T(x) B(x) is the quotient of differentiable functions, then B(x)T'(x)+T(x)B'(x) f'(x) = [B(x)]² B'(x)T(x) – T'(x)B(x) f'(x)= = [B(x)]2 B(x)T'(x)T(x)B'(x) f'(x) = = [B'(x)]2 T'(x) f'(x) = B'(x) О f'(x) = B(x)T'(x)T(x)B'(x) [B(x)]2 B'(x)T'(x) T'(x)B'(x) f'(x)= = [B'(x)]2
Transcribed Image Text:Theorem: Quotient Rule If f(x) = T(x) B(x) is the quotient of differentiable functions, then B(x)T'(x)+T(x)B'(x) f'(x) = [B(x)]² B'(x)T(x) – T'(x)B(x) f'(x)= = [B(x)]2 B(x)T'(x)T(x)B'(x) f'(x) = = [B'(x)]2 T'(x) f'(x) = B'(x) О f'(x) = B(x)T'(x)T(x)B'(x) [B(x)]2 B'(x)T'(x) T'(x)B'(x) f'(x)= = [B'(x)]2
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