Theorem: Quotient Rule If f(x) = T(x) B(x) is the quotient of differentiable functions, then f'(x) = B(x)T'(x)+T(x)B'(x) [B(x)]² B'(x)T(x) – T'(x)B(x) f'(x)= = [B(x)]2 B(x)T'(x)T(x)B'(x) f'(x) = = [B'(x)]2 T'(x) f'(x) = B'(x) О f'(x) = B(x)T'(x)T(x)B'(x) [B(x)]2 B'(x)T'(x) T'(x)B'(x) f'(x): = [B'(x)]2
Theorem: Quotient Rule If f(x) = T(x) B(x) is the quotient of differentiable functions, then f'(x) = B(x)T'(x)+T(x)B'(x) [B(x)]² B'(x)T(x) – T'(x)B(x) f'(x)= = [B(x)]2 B(x)T'(x)T(x)B'(x) f'(x) = = [B'(x)]2 T'(x) f'(x) = B'(x) О f'(x) = B(x)T'(x)T(x)B'(x) [B(x)]2 B'(x)T'(x) T'(x)B'(x) f'(x): = [B'(x)]2
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Theorem: Quotient Rule
If f(x) =
T(x)
B(x)
is the quotient of differentiable functions, then
B(x)T'(x)+T(x)B'(x)
f'(x) =
[B(x)]²
B'(x)T(x) – T'(x)B(x)
f'(x)=
=
[B(x)]2
B(x)T'(x)T(x)B'(x)
f'(x) =
=
[B'(x)]2
T'(x)
f'(x) =
B'(x)
О
f'(x) =
B(x)T'(x)T(x)B'(x)
[B(x)]2
B'(x)T'(x) T'(x)B'(x)
f'(x)=
=
[B'(x)]2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2c634e35-7043-49c5-9dee-7b7e699d3d45%2Fcbfc825d-954b-470d-bd44-19ef591bccfe%2Fsgts5l_processed.png&w=3840&q=75)
Transcribed Image Text:Theorem: Quotient Rule
If f(x) =
T(x)
B(x)
is the quotient of differentiable functions, then
B(x)T'(x)+T(x)B'(x)
f'(x) =
[B(x)]²
B'(x)T(x) – T'(x)B(x)
f'(x)=
=
[B(x)]2
B(x)T'(x)T(x)B'(x)
f'(x) =
=
[B'(x)]2
T'(x)
f'(x) =
B'(x)
О
f'(x) =
B(x)T'(x)T(x)B'(x)
[B(x)]2
B'(x)T'(x) T'(x)B'(x)
f'(x)=
=
[B'(x)]2
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