Theorem (Lebesgue dominated convergence theorem) Let {f} be a sequence of mea- surable functions converging in measure to f. If there exists a non-negative summable function such that f(x) ≤ (x) a.e. on E for each n = N, then lim fn(x)dx=ff(x)dx. 11-00 E
Theorem (Lebesgue dominated convergence theorem) Let {f} be a sequence of mea- surable functions converging in measure to f. If there exists a non-negative summable function such that f(x) ≤ (x) a.e. on E for each n = N, then lim fn(x)dx=ff(x)dx. 11-00 E
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.1: Infinite Sequences And Summation Notation
Problem 72E
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![Theorem (Lebesgue dominated convergence theorem) Let {f} be a sequence of mea-
surable functions converging in measure to f. If there exists a non-negative summable function
such that f (x) ≤ (x) a.e. on E for each n € N, then
lim ffn (x)dx=ff(x)dx.
11-0
E](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd8acff42-1025-4992-8114-0bd25c486b83%2F9945dd0e-eb62-40fb-b60d-d756849c251d%2F6outuhd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Theorem (Lebesgue dominated convergence theorem) Let {f} be a sequence of mea-
surable functions converging in measure to f. If there exists a non-negative summable function
such that f (x) ≤ (x) a.e. on E for each n € N, then
lim ffn (x)dx=ff(x)dx.
11-0
E
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