Theorem: If A has a repeated real root λ with corresponding eigenvector K₁ then all solutions of X' = A X are of the form: W x ν = (*) -K et K₁₂ (te K₁ + e₁t W2 where (A - I) (B)- = K₁. Theorem: Let λ₁ = α + i ẞ be a complex eigenvalue of the coefficient matrix A with corresponding eigenvector K₁ = B₁ + i B2. Then all solutions of X' = A X are of the form: ()- That is: }) y = c₁ (B₁ αι cos ẞt - B2 sin ẞt) eat + C₂ (B₂ cos ẞt + B₁ sin ẞt) eat. |= c₁ (Re(K₁) cos ẞt - Im(K₁) sin ẞt) eat + C₂ (Im(K₁) cos ẞt + Re(K₁) sin ẞt) eat.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Using the attached theorms, Solve dx/dt =2x+3y , dy/dt=6x+5y with initial conditions x(0) = 8, y(0) = 1.

Theorem: If A has a repeated real root λ with corresponding eigenvector K₁ then all
solutions of X' = A X are of the form:
W
x
ν
=
(*) -K
et K₁₂ (te K₁ + e₁t
W2
where (A - I)
(B)-
= K₁.
Theorem: Let λ₁ = α + i ẞ be a complex eigenvalue of the coefficient matrix A with corresponding
eigenvector K₁ = B₁ + i B2. Then all solutions of X' = A X are of the form:
()-
That is:
})
y
= c₁ (B₁
αι
cos ẞt - B2 sin ẞt) eat + C₂ (B₂ cos ẞt + B₁ sin ẞt) eat.
|= c₁ (Re(K₁) cos ẞt - Im(K₁) sin ẞt) eat + C₂ (Im(K₁) cos ẞt + Re(K₁) sin ẞt) eat.
Transcribed Image Text:Theorem: If A has a repeated real root λ with corresponding eigenvector K₁ then all solutions of X' = A X are of the form: W x ν = (*) -K et K₁₂ (te K₁ + e₁t W2 where (A - I) (B)- = K₁. Theorem: Let λ₁ = α + i ẞ be a complex eigenvalue of the coefficient matrix A with corresponding eigenvector K₁ = B₁ + i B2. Then all solutions of X' = A X are of the form: ()- That is: }) y = c₁ (B₁ αι cos ẞt - B2 sin ẞt) eat + C₂ (B₂ cos ẞt + B₁ sin ẞt) eat. |= c₁ (Re(K₁) cos ẞt - Im(K₁) sin ẞt) eat + C₂ (Im(K₁) cos ẞt + Re(K₁) sin ẞt) eat.
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