Theorem: For any given area A, the rectangle that has the least perimeter is a square. Part I: Complete the proof that is outlined below. Submit each step as part of your final answer. Proof: In terms of the side length, x, the formula for the perimeter of a square: P- 2x+ Define a new variable: y = VA 1. In terms of the new variable, v, compute and simplify: 2 =, 2. Rewrite this equation to get the formula for P alone on one side. Replace the formula by the variable P. Write that result by completing the equation below: P= 22 + Part Il: 1. In the equation above, P is a function of v, and A is a constant. The minimum value of this function occurs when v = 2. Explain why this is true. 3. Substitute this value of v into y = x - VA and solve for x. 4. This is the value of the length x that yields the minimum value of P. For this length, what is the value of the width? 5. How do the length and width compare?

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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SECTION 3 OF 3
QUESTION
Theorem: For any given area A, the rectangle that has the least perimeter is a square.
Part I:
Complete the proof that is outlined below. Submit each step as part of your final answer.
Proof:
In terms of the side length, x, the formula for the perimeter of a square: P= 2x+
2A
Define a new variable: y =
VĀ
1. In terms of the new variable, v, compute and simplify: 2 =
2. Rewrite this equation to get the formula for P alone on one side. Replace the formula by the variable
P. Write that result by completing the equation below:
P= 22 +
Part II:
1. In the equation above, P is a function of v, and A is a constant. The minimum value of this function
occurs when v =
2. Explain why this is true.
VĀ
and solve for x.
3. Substitute this value of v into v -
4. This is the value of the length x that yields the minimum value of P. For this length, what is the value
of the width?
5. How do the length and width compare?
UPLOAD
Transcribed Image Text:SECTION 3 OF 3 QUESTION Theorem: For any given area A, the rectangle that has the least perimeter is a square. Part I: Complete the proof that is outlined below. Submit each step as part of your final answer. Proof: In terms of the side length, x, the formula for the perimeter of a square: P= 2x+ 2A Define a new variable: y = VĀ 1. In terms of the new variable, v, compute and simplify: 2 = 2. Rewrite this equation to get the formula for P alone on one side. Replace the formula by the variable P. Write that result by completing the equation below: P= 22 + Part II: 1. In the equation above, P is a function of v, and A is a constant. The minimum value of this function occurs when v = 2. Explain why this is true. VĀ and solve for x. 3. Substitute this value of v into v - 4. This is the value of the length x that yields the minimum value of P. For this length, what is the value of the width? 5. How do the length and width compare? UPLOAD
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