Theorem 3 Assume that a <1 and 16 (e +g +s) – d (c+f +r)|+|c(d +g +s) – e (b+ f +r)| +|f (d +e +s) – g (b +c+r)I+|r (d +e +g) – s (b +c+ f)| < (d + e+g) (b+c+ f), - S (12) then the positive equilibrium point (7) of Eq.(1) is locally asymptotically sta- ble. Proof: It follows by Theorem 1 that Eq.(10) is asymptotically stable if all roots of Eq.(11) lie in the open disk le1| + |po| < 1, |Al < 1 that is if |P4| + \p3| + p2| + |(1 – a) [b (e +g + s) (d +e +g+s) (6 +c + f +r) d (c + f +r)] Jal + |(1 – a) [c (d +g +s) (d +e +g+s) (b +c + f + r) (1 – a) [ƒ (d+e+ s) (d +e +g+ s) (6 +c+ f+r) (1 – a) [r (d + e +g) · (d +e +g+s) (6 +c + f +r) < 1, e (b +f +r)] | g (b +c+r)] s (b +c+ f)]| and so |(1 – a) [b (e +g +s) – d (c + f +r)]| (d +e +g+s) (b+ c + f +r) (1 – a) [c (d +g + s) – e(b + f +r)]| (d +e +g+s) (b +c+ f + r) (1 – a) [f (d +e +s) (d +e +g+s) (b +c +f +r) (1 – a) [r (d +e +g) – s (b +c+ f)] (d +e +g+s) (b +c + f +r) a < 1, - g (b +c+r)] < (1-а), or |6 (e +g +s) – d (c+f +r)| + |c (d +g+ s) – e (b+f +r)| +If (d +e +s) – g (b +c+r)|+|r (d +e +g) – s (b +c+ f)| (d +e +g) (b+c+ f).) Thus, the proof is now completed.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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The objective of this article is to investigate some qualitative behavior of
the solutions of the nonlinear difference equation
бxn-1 + сх,n-2 + fxn-3 + rtn-4
Xn+1 = axn +
n = 0, 1, 2, .. (1)
dxn-1 + en-2 + gxn-3 + sxn-4
where the coefficients a, b, c, d, e, f, g,r, s E (0, 0), while the initial con-
ditions x-4,X –3,X –2, x – 1, xo are arbitrary positive real numbers. Note that
the special cases of Eq.(1) has been studied discussed in [11] when f = g =
0 and Eq. (1) has been studied discussed in [35] in the special case
r = s =
when r = s = 0.
Transcribed Image Text:The objective of this article is to investigate some qualitative behavior of the solutions of the nonlinear difference equation бxn-1 + сх,n-2 + fxn-3 + rtn-4 Xn+1 = axn + n = 0, 1, 2, .. (1) dxn-1 + en-2 + gxn-3 + sxn-4 where the coefficients a, b, c, d, e, f, g,r, s E (0, 0), while the initial con- ditions x-4,X –3,X –2, x – 1, xo are arbitrary positive real numbers. Note that the special cases of Eq.(1) has been studied discussed in [11] when f = g = 0 and Eq. (1) has been studied discussed in [35] in the special case r = s = when r = s = 0.
Theorem 3 Assume that a < 1 and
|b (e +g + s) – d (c+ f +r)|+ |c (d +g +s) – e (b+ f +r)|
+|f (d +e +s) – g (b +c+r)I+ |r (d +e +g)
(d +e+ g) (b+ c+ f),
s (b +с+f)|
(12)
then the positive equilibrium point (7) of Eq. (1) is locally asymptotically sta-
ble.
Proof: It follows by Theorem 1 that Eq.(10) is asymptotically stable if all
roots of Eq.(11) lie in the open disk is |A| < 1 that is if |e4|+ |p3| + |p2|+
\ei|+ \po] < 1,
(1 – a) [b (e +g + s)
|a| +
(d +e +g+ s) (b + с +f+r)
d (c +f +r)]
(1 – a) [c (d +g +s)
(d +e +g+ s) (b +c + f + r)
|(1 – a) [f (d+ e + s)
(d + e +g+ s) (b +c+ ƒ +r)
(1– a) [r (d+ e + 9) – s (b +c+ f).
(d +e +g+s) (b+c + f +r)
< 1,
e (b + f +r)] |
g (b +c+r)]
and so
- - a) [b (e +g + s) – d (c + f +r)]
(d +e +g+ s) (b+ c + f +r)
|(1 – a) [e (d +g + s)
(d +e +g+s) (b +c+ f +r)
|(1 – a) [f (d + e +s)
(d +e +g+s) (b +c + f +r)
(1 – a) [r (d +e +g)
(d +e +g+s) (b +c + f +r)
e (b + f +r)]
g (b +c+r)]
(b +c+ f)]
- S
< (1- а),
а <1,
or
16 (e + g +s) – d (c+ f +r)|+ |c(d +g+s) – e (b+ f +r)|
+\f (d +e +s) – g (b +c+r)|+ |r (d +e + g) – s (b +c+ f)|
(d +e +g) (b+c+ f).)
Thus, the proof is now completed.
Transcribed Image Text:Theorem 3 Assume that a < 1 and |b (e +g + s) – d (c+ f +r)|+ |c (d +g +s) – e (b+ f +r)| +|f (d +e +s) – g (b +c+r)I+ |r (d +e +g) (d +e+ g) (b+ c+ f), s (b +с+f)| (12) then the positive equilibrium point (7) of Eq. (1) is locally asymptotically sta- ble. Proof: It follows by Theorem 1 that Eq.(10) is asymptotically stable if all roots of Eq.(11) lie in the open disk is |A| < 1 that is if |e4|+ |p3| + |p2|+ \ei|+ \po] < 1, (1 – a) [b (e +g + s) |a| + (d +e +g+ s) (b + с +f+r) d (c +f +r)] (1 – a) [c (d +g +s) (d +e +g+ s) (b +c + f + r) |(1 – a) [f (d+ e + s) (d + e +g+ s) (b +c+ ƒ +r) (1– a) [r (d+ e + 9) – s (b +c+ f). (d +e +g+s) (b+c + f +r) < 1, e (b + f +r)] | g (b +c+r)] and so - - a) [b (e +g + s) – d (c + f +r)] (d +e +g+ s) (b+ c + f +r) |(1 – a) [e (d +g + s) (d +e +g+s) (b +c+ f +r) |(1 – a) [f (d + e +s) (d +e +g+s) (b +c + f +r) (1 – a) [r (d +e +g) (d +e +g+s) (b +c + f +r) e (b + f +r)] g (b +c+r)] (b +c+ f)] - S < (1- а), а <1, or 16 (e + g +s) – d (c+ f +r)|+ |c(d +g+s) – e (b+ f +r)| +\f (d +e +s) – g (b +c+r)|+ |r (d +e + g) – s (b +c+ f)| (d +e +g) (b+c+ f).) Thus, the proof is now completed.
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