THEOREM 2.3. Let X be a finite-dimensional inner product space and let E be a projection. Then the following statements are equivalent. (1) E is normal; (2) E is self-adjoint; (3) E is the orthogonal projection on its range. Proof (3) ⇒ (1). Let x, y e X. Then, since E is idempotent, x - Ex = N(E) = R(E)¹ Ey = R(E). (x - Ex, Ey)=0 and Thus or (x, Ey) = (Ex, Ey) = (x, E*Ey) (for any x, y € X). Therefore E = E*E and the proof becomes the same as in proving (1) ⇒ (2); that is, it follows that E is self-adjoint, which certainly implies that E is normal, and com- pletes the proof of the theorem.
THEOREM 2.3. Let X be a finite-dimensional inner product space and let E be a projection. Then the following statements are equivalent. (1) E is normal; (2) E is self-adjoint; (3) E is the orthogonal projection on its range. Proof (3) ⇒ (1). Let x, y e X. Then, since E is idempotent, x - Ex = N(E) = R(E)¹ Ey = R(E). (x - Ex, Ey)=0 and Thus or (x, Ey) = (Ex, Ey) = (x, E*Ey) (for any x, y € X). Therefore E = E*E and the proof becomes the same as in proving (1) ⇒ (2); that is, it follows that E is self-adjoint, which certainly implies that E is normal, and com- pletes the proof of the theorem.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:THEOREM 2.3. Let X be a finite-dimensional inner product space and let E be a
projection. Then the following statements are equivalent.
(1) E is normal;
(2) E is self-adjoint;
(3) E is the orthogonal projection on its range.
Proof (3) ⇒ (1). Let x, y = X. Then, since E is idempotent,
x - Ex = N(E) = R(E)¹
Ey = R(E).
(x - Ex, Ey) = 0
and
Thus
or
(x, Ey) = (Ex, Ey) = (x, E* Ey)
(for any x, y e X).
Therefore E = E*E and the proof becomes the same as in proving (1) ⇒ (2); that is,
it follows that E is self-adjoint, which certainly implies that E is normal, and com-
pletes the proof of the theorem.
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