Theorem 2. Suppose that {n} is solutions of (3 ) and the initial value xo is an arbitrary nonzero real number . Let xo = a .Then ,by using the notations(III) , the solutions of (3) are given by: a A1 n-1 a Xn = An (IV) i =1 where xo = a and n > 2 Proof. Firstly, a x 1 = (x 0)ª-1 + a A1 Now ,by mathematical induction , we will prove that equations{IV} are true for n > 2. In the begining we try to prove that equations{IV} are true for n=2. 2-1 a a II 42 I 2 = (x 1)ª–1 + a G-1 + a A1 A2 A2 i =1 Now suppose that the equations{IV} is true for n = r.This means that r-1 a Xr = A, i =1 Finally we prove that the equations{IV} is true for n =r+1. Xr+1 = 9-1 + a i =1 r-1 i =1 a T-1 A,{a9-1 TI A§ª-2)(«¬-1) +a4f-1} i =1 -2 a a i =1 Ar+1 i =1 which complete the proof. Now we are going to give the general solution for the following nonlinear rational quadratic differ- ence equations of order two : Xn-1 Xn+1 = ((4)) "n-1 +a where a # -a and æ², # -a To do this we motivate by the following notations: suppose that x-1 = a1and xo = a2 . Let A1,1 = af +a and A1,2 = az +a Also consider the following notations: A2,1 = af + aA?‚1 Moreover we consider A2.2 = až + aA},2 A3,1 = af A?1 + aAž1 A4.1 = af A?, A31 + a Až, A3,2 = až A72 + aA32 , A4,2 = a3A?2A3 2+ aA32 In general we have p-2 Ap,1 = a? II 41 + aA-1,1 where p > 3 (V) i =1 p-2 Ap2 = aII A?2 +aAž-1,2 where p > 3. i =1
Theorem 2. Suppose that {n} is solutions of (3 ) and the initial value xo is an arbitrary nonzero real number . Let xo = a .Then ,by using the notations(III) , the solutions of (3) are given by: a A1 n-1 a Xn = An (IV) i =1 where xo = a and n > 2 Proof. Firstly, a x 1 = (x 0)ª-1 + a A1 Now ,by mathematical induction , we will prove that equations{IV} are true for n > 2. In the begining we try to prove that equations{IV} are true for n=2. 2-1 a a II 42 I 2 = (x 1)ª–1 + a G-1 + a A1 A2 A2 i =1 Now suppose that the equations{IV} is true for n = r.This means that r-1 a Xr = A, i =1 Finally we prove that the equations{IV} is true for n =r+1. Xr+1 = 9-1 + a i =1 r-1 i =1 a T-1 A,{a9-1 TI A§ª-2)(«¬-1) +a4f-1} i =1 -2 a a i =1 Ar+1 i =1 which complete the proof. Now we are going to give the general solution for the following nonlinear rational quadratic differ- ence equations of order two : Xn-1 Xn+1 = ((4)) "n-1 +a where a # -a and æ², # -a To do this we motivate by the following notations: suppose that x-1 = a1and xo = a2 . Let A1,1 = af +a and A1,2 = az +a Also consider the following notations: A2,1 = af + aA?‚1 Moreover we consider A2.2 = až + aA},2 A3,1 = af A?1 + aAž1 A4.1 = af A?, A31 + a Až, A3,2 = až A72 + aA32 , A4,2 = a3A?2A3 2+ aA32 In general we have p-2 Ap,1 = a? II 41 + aA-1,1 where p > 3 (V) i =1 p-2 Ap2 = aII A?2 +aAž-1,2 where p > 3. i =1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Show me the steps of determine blue and inf is here
Expert Solution
Step 1
Given : nonlinear rational difference equation
where .
Other notation :
(III)
and equations {IV}
(IV)
where ,
To prove : equations {IV} is true for .
Step by step
Solved in 3 steps
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