Then we get bM + cM + fm+ rm bm + cm + ƒM+rM М -аМ+ аnd m = am+ dM + eM + gm + sm dm + em + gM + sM' or M (b+ c) + (f+r) m M (d + e) + (g +s) m m (b+c) + (f +r) M m (d + e) + (g + s) M М (1 —а) and m(1 -а) 3 From which we have (9+s) (1 — а) Мт %3D М (b+ с) + (f +r)m - (1-а) (d+е) М? (36) and (g + s) (1 — а) Мт %3D т (b + с) + (f +r) M - (1— а) (d+е)т?. (37) From (36) and (37), we obtain (m – M) {[(b+ c) – (f + r)] – (1 – a) (d + e) (m + M)} = 0. (38) Since a < 1 and (f +r) > (b+ c), we deduce from (38) that M = m. It follows by Theorem 2, that ã of Eq.(1) is a global attractor and the proof is now completed.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Explain the determine green

Then we get
ьМ + сМ + fm + rm
bm + ст + fM + rM
dm + em + gМ + sM
М — аМ+
аnd
т — ат+
dM + eM + gт + sm
or
М(6+ с) + (f + r) m
а)
M (d + e) + (g + s) m
т (b + c) + (f +r) M
т (d+e)+ (g+ s) M'*
М (1
аnd m (1 -— а)
From which we have
(9 + s) (1 — а) Мт — M (b+с) + (f +r) т — (1 — а) (d + е) М2
(36)
and
(9 + s) (1 — а) Мт — т (b + с) + (f +r) M — (1— а) (d + е) т?.
(37)
-
From (36) and (37), we obtain
(т —
-M) {(6 + с) — (f +)] - (1 — а) (ӑ +е) (m+ M)} — 0.
(38)
Since a < 1 and (f + r) > (b+ c), we deduce from (38) that M = m. It
follows by Theorem 2, that ã of Eq.(1) is a global attractor and the proof is
now completed.
Transcribed Image Text:Then we get ьМ + сМ + fm + rm bm + ст + fM + rM dm + em + gМ + sM М — аМ+ аnd т — ат+ dM + eM + gт + sm or М(6+ с) + (f + r) m а) M (d + e) + (g + s) m т (b + c) + (f +r) M т (d+e)+ (g+ s) M'* М (1 аnd m (1 -— а) From which we have (9 + s) (1 — а) Мт — M (b+с) + (f +r) т — (1 — а) (d + е) М2 (36) and (9 + s) (1 — а) Мт — т (b + с) + (f +r) M — (1— а) (d + е) т?. (37) - From (36) and (37), we obtain (т — -M) {(6 + с) — (f +)] - (1 — а) (ӑ +е) (m+ M)} — 0. (38) Since a < 1 and (f + r) > (b+ c), we deduce from (38) that M = m. It follows by Theorem 2, that ã of Eq.(1) is a global attractor and the proof is now completed.
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