Then, for testing the iodide test, the acidified solution of sodium iodide (NaI) reacts with Fe(NO3)3 , the following reaction takes place and showed FeI3  and NaNO3  are formed as products. The formed FeI3 is dark yellow to brown in colour.   3NaI + Fe(NO3)3  → FeI3  + 3NaNO3     After the addition of dichloro-methane the colour still remains the same. The equation is as follows:   2FeI3 + 3CH2Cl2 → 3CH2I2 + 2FeCl3   All the above reactions involved in the test are double displacement reactions. So, the above test is positive (formation of dark yellow to brown color solution), it indicates the presence of iodide ion in the solution.   Question : Explain more about this experiment results.

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Then, for testing the iodide test, the acidified solution of sodium iodide (NaI) reacts with Fe(NO3)3 , the following reaction takes place and showed FeI and NaNO are formed as products. The formed FeI3 is dark yellow to brown in colour.

 

3NaI + Fe(NO3) → FeI + 3NaNO 

 

After the addition of dichloro-methane the colour still remains the same. The equation is as follows:

 

2FeI3 + 3CH2Cl2 → 3CH2I2 + 2FeCl3

 

All the above reactions involved in the test are double displacement reactions. So, the above test is positive (formation of dark yellow to brown color solution), it indicates the presence of iodide ion in the solution.

 

Question : Explain more about this experiment results. 

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