The Centers for Disease Control reported the percentage of people 18 years of age and older who smoke (CDC website, December 14, 2014). Suppose that a study designed to collect new data on smokers and nonsmokers uses a preliminary estimate of the proportion who smoke of .28. a. How large a sample should be taken to estimate the proportion of smokers in the population with a margin of error of .02 (to the nearest whole number)? Use 95% confidence.   b. Assume that the study uses your sample size recommendation in part (a) and finds 520 smokers. What is the point estimate of the proportion of smokers in the population (to 4 decimals)?   c. What is the 95% confidence interval for the proportion of smokers in the population (to 4 decimals)?

Q: In estimating the population mean with the population standard deviation unknown, if the sample size…

A: Given that, Population standard deviation is unknown and sample size (n) = 27

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A: Given: n= 1031 ,x= 545 need to find point estimation for p.

Q: find the margin of error in estimatingu at the 92% level of confidence.

A:

Q: A 95% confidence interval of 19.1 months to 48.7 months has been found for the mean duration of…

A: Given data: Given confidence interval = (19.1 , 48.7 ) Standard deviation  = 42 months Mean = 36.2

Q: A Seattle consumer agency believes that plumbers’ rates are too high and wants to estimate the mean…

A: GivenConfidence Interval(c)=95%Margin of Error(E)=3%=0.03Let…

Q: The U.S. Department of Health, Education, and Welfare collected sample data for 1555 women aged 18…

A: given data,n=1555DF=n-1=1555-1=1554x¯=193.7σ=42.0CI=0.97α=1-0.97=0.03E=?

Q: A recent survey in the United States reported the prevalence of a sexually transmitted disease…

A: Given information- Sample proportion, p = 1.7% We have given 95% Confidence interval is = (1.4%,…

Q: A recommendation for the amount of vitamin C that a person should have per day is 75 mg. A…

A: given that

Q: If a 90% confidence interval for the mean is found to be (1.25,4.75) using a sample of n=100, find…

A:

Q: A recent survey found that 58% of U.S. adults use their smartphones to research and shop for…

A: The expression is  The margin of error is given as 5.3%.

Q: In a study of government financial aid for college students, it becomes necessary to estimate the…

A: The provided information are: Confidence level = 90% = 0.90 Margin of error (E) = 0.05 From the…

Q: Blood pressure values are often reported to the nearest  5 mmHg (100, 105, 110, etc.). Suppose the…

A: Given: Sample size n = 9 Formula Used: Median = 2(n+1)4thterm

Q: If [330, 610] is a confidence interval for the population mean. Find the margin of eror. Select one:…

A: The upper limit of the confidence interval is (U) = 610 The lower limit of the confidence interval…

Q: Suppose you are given the question: "At Max tire sales, the 5% of the tires they sell are defective.…

A: From the given information, the sample size (n) is 8.

Q: Starting salaries of 120 college graduates who have taken a statistics course have a mean of…

A:

Q: Suppose that you are attempting to estimate the weight of 600 parts. In order to use the infinite…

A:

Q: estimate of for the following. E = .17, ? = .90, confidence level = 99%

A: (1) We have given that,  Population proportion (p) = 0.90, margin of error (E) = 0.17 and…

Q: When estimating the mean age of a population of 5000 individuals, a simple random sample of 50…

A:

Q: 2. The mean and standard deviation of the blood sugar level of randomly selected 50 patients in a…

A:

Q: Consider a dataset with standard deviation 2, mean 6.2, and a total of 186 data points. What is the…

A: The given data is - Standard deviation (σ)=2 Mean(x)=6.2 Sample size(n)=186

Q: You want to create a Z-interval for a population mean, using table C, with the following…

A: From the provided information, Sample size (n) = 25 Mean (x̅) = 34.2 Population standard deviation…

Q: Decide whether the following scenarios are example of type 1 error or type 2 error or neither? Use…

A: Explanation: The investigator is specifically interested to test whether the mean weight of babies…

Q: "A between-subjects ANOVA was found to be significant, with a SS-Between = 210.29 and SS-Within =…

A: Given: SS between = 210.29 SS total = 161.76 A sample measure of effect size is given by "η2=" (SS…

Q: a. Find the best point estimate of the mean. b. Find the 95% confidence interval of the mean score…

A: According to the answering guidelines, we can answer only three subparts of a question and the rest…

Q: intended population

A: A population is the entire group that you want to draw conclusions about   Intended population:…

Q: An economist would like to estimate the mean amount of money that a family spends to within $45. If…

A:

Q: The dispersion of the copper determination in the seawater sample is 2.24%. How many parallel…

A:

Q: An auditor, examining a total of 830 accounts receivable of a corporation, took a random sample of…

A: We have to find population mean ...

Q: Suppose a government department would like to investigate the relationship between the cost of…

A: The data shows the a random sample of 10 homes heating cost and square footage.

Q: Your state is considering raising the legal age for consumption of alcoholic beverages to 21 years…

A: p = 0.5 Margin of error = 0.01

Q: With 95% confidence, what is the margin of error when estimating a population mean when n = 100 and…

A:

Q: The average chef at a restaurant earns $17 an hour with a deviation of $1.75. What are the chances…

A:

Q: When asked, "Do kids regularly carry weapons in your school?" 14,252 students said yes, and 115,336…

A: From the provided information,Confidence level = 95%

Q: period, ercial boat trips down the Colorado Riv Compute a 5% trimmed mean for Upper ne nearest…

A: Trimmed mean is defined as a method of averaging that trimmed out or we can say remove a small…

Q: You are conducting a study to estimate the mean height of students in a university. The university…

A: To calculate the sample size required to estimate the mean height of students in the university with…

Q: A grocer finds that the cantaloupes in his store have weights with mean 0.7 kg and standard…

A: Given, Mean weight of cantaloupes is 700 gm. Standard deviation is 53 gm

Q: An arborist is interested in determining the mean diameter (in centimeters) of mature white oak…

A: Given: n=7, x=49.09 and s=13.8.   At 95% confidence level, the value of z is 1.96.

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.