The y-coordinate of a particle in curvilinear motion isgiven by y = 11.3+³ - 11.7t, where y is in inches and tis inseconds. Also, the particle has an acceleration in the x-direction given by ax = 12.6t in./sec². If the velocity of theparticle in the x-direction is 3.9 in./sec when t = 0,calculate the magnitudes of the velocity v andacceleration a of the particle when t = 1.6 sec. Constructv and a in your solution.Answers: When t = 1.6 sec,v = in./seca = in./sec²

Given, y=11.3t3-11.7t inax=12.6t in/s2v0x=3.9 in/s

Answered: The y-coordinate of a particle in…

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