The x y-coordinate plane is given. A curve with 2 parts is graphed. The first part is linear, enters the window in the second quadrant, goes down and right, crosses the x-axis at x = −1, and ends at the open point (0, −1). The second part is linear, begins at the closed point (0, 2), goes down and right, crosses the x-axis at x = 2, and exits the window in the fourth quadrant. Determine whether f is continuous on its domain. continuous not continuous
The x y-coordinate plane is given. A curve with 2 parts is graphed. The first part is linear, enters the window in the second quadrant, goes down and right, crosses the x-axis at x = −1, and ends at the open point (0, −1). The second part is linear, begins at the closed point (0, 2), goes down and right, crosses the x-axis at x = 2, and exits the window in the fourth quadrant. Determine whether f is continuous on its domain. continuous not continuous
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter1: Equations And Graphs
Section: Chapter Questions
Problem 8T
Related questions
Question
The graph of a function f is given.
The x y-coordinate plane is given. A curve with 2 parts is graphed.
- The first part is linear, enters the window in the second quadrant, goes down and right, crosses the x-axis at x = −1, and ends at the open point (0, −1).
- The second part is linear, begins at the closed point (0, 2), goes down and right, crosses the x-axis at x = 2, and exits the window in the fourth quadrant.
Determine whether f is continuous on its domain.
continuous
not continuous
If it is not continuous on its domain, say why.
lim
x→0
f(x) ≠ f(0)
lim
x→0+
f(x) ≠
lim
x→0−
f(x), so
lim
x→0
f(x) does not exist.
The graph has discontinuities at the end points.
The graph is continuous on its domain.
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