The work done by the force F = 4 î - 3j + 2 k to displace a body from point (3,2,-1)to point (2,-1,4) is:b: - (i + 3j- 5k)c: -4i + 9j + 10kа: 19d: 15A = î+ j, B = i - k and C = i+j-k, the scalar triple product is equal to:d: i%3D%3Dа: -1b:-ic: 1

The position vectors can be determined as, The displacement vector can be determined as,

The work done by the force F = 4 i - 3j + 2 k to displace a body from point (3,2,-1) to point (2,-1,4) is: b: - (i+ 3 j- 5k) c: -4î + 9j+ 10k a: 19 d: 15 A = î+ j, B = î-k and C î+ j-k, the scalar triple product is equal to: %3D %3D a: -1 b:-i c: 1 d: i

The work done by the force F = 4 i - 3j + 2 k to displace a body from point (3,2,-1) to point (2,-1,4) is: b: - (i+ 3 j- 5k) c: -4î + 9j+ 10k a: 19 d: 15 A = î+ j, B = î-k and C î+ j-k, the scalar triple product is equal to: %3D %3D a: -1 b:-i c: 1 d: i

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

/
The moment of the force F=960-lb about the point O in Cartesian vector form is. 1 ft 4 ft 2ft Select one: O a. Mo = 1600 – 3200A O b. Mo = -200j + 400k Oc. Mo =-200; – 400k O d. Mo= 200; + 400k 1:15 PM
Cartesian coordinat system; A(0,0,0) B(3,4,0) C(3,4,4) A/ M АВ AB OM, F =-20i+10 j +15k N is applied to point C Moment of force F about point A; M, B/ M = AC ® F C/ M AB = AB O F Moment of force F about point B; M, D/ M, = BC ® F Moment of force F about line AB; MAB Which following one is WRONG? E/ M AB OM, AB
Cartesian coordinat system; A(0,0,0) B(3,4,0) C(3,4,4) F = -20i+10j +15k N is applied to point C Moment of force F about point A; M, Moment of force F about point B; M, Moment of force F about line AB; MAE АВ Which following one is TRUE? Magnitude of moment about AB line {M(AB)} of force F is equal to the vector product of unit vector (3i+4j) and Moment vector of the force F about O A) point A. Moment magnitude of force Fabout AB line {M(AB)} is equal to the scaler product of unit vector (0.6 i + 0.8 j) and Moment vector of force F about point B) А. Moment vector of force F about AB line {M(AB)} is equal to the vector product the force Fand unit vector (0.6 i+ 0.8 i) Magnitude of moment about AB line {M(AB)} of force F is equal to the vector product of unit vector (0.6 i + 0.8 j) and Moment vector of the force F about D) point A. E) NONE
The moment of the force F=120-lb about the point O in Cartesian vector form is. F= 120 lb 1 ft 4 ft 2 ft Select one: O a. Mo = 200j - 400k -200j + 400k O b. Mo O c. Mo = -200j – 400k O d. Mo = 200j+ 400k %3D
The moment of the force F=120 lb about the point O in Cartesian vector form is. F= 120 lb 1 ft 4 ft 2 ft 4 ft Select one: O a. Mo = 200j – 400k O b. Mo = -2007 + 400k O c. Mo = -2007j – 400k O d. Mo = 200j + 400k EN
a = 4 mb = 3.2 mc = 2 mF = {-7i+4j+12k} NSpecified axis: AF Find the following: Find the z-component of the moment of F about the specified axis. Find the x-component of the moment of F about the specified axis. Find the magnitude of the moment of F about the specified axis. Find the y-component of the moment of F about the specified axis.
Consider the following vectors: • F = 10 @ 0° • G = 5 @ 180° What is the solution to F+G? O -10 @ 0° 10 5 @ 180° 7.5 @ 45° O 10 @ 0° -15 5 @ 0° -5 O 15 O -10
An L-shaped bracket is supported by a frictionless pin at A and a cable between points B and D. If pin A is the origin, point C is at (-7, 0); and pin B is at (-7, -10). The cable is attached between point B and an anchor at point D, at (-2, -14). Units are in feet. Force F acts at point C at an angle of 60o from the positive x-axis. Determine the magnitude of the moment that the force F produces about point A. Determine the tension required to hold the bracket in position.
Q 3. A frame B is rotated 90 degree about the z-axis, then translated 3 and 5 units relative to the n- and o-axes respectively, then rotated another 90 degree about the n-axis, and finally, 90 degree about the y-axis. Find the new location and orientation of the frame. O 1 0 1 1 0 1 B = - 1 1 1
F1 F2 F3 A b F4 D F5 Consider the following values: - a = 25 m; b 5 m; c = 25 m; d = 5 m; F1 = 4 kN; F2 = 5 kN; F3 = 6 kN; F4 = 7 kN; F5 = 8 kN; a = 30°, 0 = 60° %3D B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 75.8 kN.m b) 32.7 kN.m c) - 14.6 kN.m d) 72.9 kN.m e) 27.1 kN.m - 66.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) - 198.8 kN.m b) 212.7 kN.m c) - 121.6 kN.m d) 98.9 kN.m e) 125.4 kN.m f) -170.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - 96.7 kN.m b) 251.1 kN.m c) - 114.6 kN.m d) 217.9 kN.m 154.1 kN.m f)-177.7 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 198 kN.m b) 127 kN.m c) – 219 kN.m d) 369 kN.m e) 151 kN.m f) - 171 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Setting
The moment of the force F=120-lb about the point O in Cartesian vector form is. F-120 lb 1ft 4 ft 2 ft Select one: a. Mo = 200j - 400k b. Mo = -200j+ 400k c. Mo = -200j- 400k O d. Mo = 200j+ 400k