Problem 2:The width of a rectangular slit is measured in the laboratoryby means of its diffraction pattern at a distance of 2 m fromthe slit. When illuminated normally with a parallel beam oflaser light (632.8 nm), the distance between the third mini-ma on either side of the principal maximum is measured.An average of several tries gives 5.625 cm.a. Assuming Fraunhofer diffraction, what is the slit width?b. Is the assumption of far-field diffraction justified in thiscase? What is the ratio L/Lmin?

Answered: Image /qna-images/answer/419e4412-8b3d-4733-850f-7cdd2ec49eab.jpg

Answered: The width of a rectangular slit is…

Similar questions

The figure below shows the standard setup for Young's double-slit experiment. The spacing between the slits is d, and the screen is a distance L away from the slits. The derivation of the two-slit interference conditions assumes that the two lines of sight to a point P are parallel, since L>d, allowing us to approximate the path length difference as 42= dsıne. How 3.00 cm, d = 0.740 mm, and 0 = good is this approximation? Suppose that L = approximation for a case where L is closer to d.) 9.00°. (Under normal experimental conditions, L/d would be much larger than this, but we want to test the Use geometry and trigonometry to compute the value for the actual path length difference A2. Enter your answer as a positive value. 337.3 m Incorrect. Tries 2/100 Previous Tries Submit Answer By what percentage does this value differ from the approximation Al=dsint? (Enter your answer as a positive number, without the percent sign. Be sure to keep lots of digits in your calculations!) Submit Answer…
The table contains data obtained during the single-slit microwave experiment with a slit width of 7 cm and a wavelength of 2.8 cm. To compare data like this with theory in Sec. 8.5, you will have to normalize both the intensity and the angular data. A. What is the normalized intensity I/I0 at 40∘? B. What is the normalized angle β/π at 25∘?
Please explain each step....You shine monochromatic light with wavelength 720 nm through a slit that has a width of 0.750 mm and observe a diffraction pattern on a screen that is 3.60 m from the slit. The intensity at the center of the central maximum is Io = 7.80 W/m2. What is the intensity of the light at a point on the pattern that is halfway between the center of the central maximum and the first minimum of interference? The purple line in the figure shows the points that are halfway between the center of the central max. and the first min.
Light of wavelength 613.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 81.5 cm from the slit. The distance on the screen between the fourth order minimum and the central maximum is 1.91 cm. What is the width ?a of the slit in micrometers (μm)?
A red laser (λ = 656 nm) is incident on a diffraction grating that has n = 1100 lines per cm.Randomized Variablesλ = 656 nmn = 1100 lines/cm Part (a) What is the angle, in radians, that the first order maximum makes, θ1? Part (b) What is the angle of the fourth order maximum, θ4, in radians?
632.8 nm) is used to calibrate a diffraction grating. If the first-order maximum occurs at 21.0°, what is the spacing between adjacent grooves in the grating? (In this problem, assume that the light is incident normally on the grating.) μm A helium-neon laser (1 =
The width of the central peak in a single-slit diffraction pattern is 5.0 mm. The wavelength of the light is 600. nm, and the screen is 1.9 m from the slit. (a.) What is the width of the slit in microns? (D= ?) (b.) What is the ratio of the intensity at 4.2mm from the center of the pattern to the intensity at the center of the pattern? (I/I0= ?)
Using monochromatic light, an interference pattern is generated on a screen 50.0 cm away from a double slit. The width of the slit is 12 μm. The third dark fringe is 6.0 cm from the center of the central maximum. What is the wavelength of the light used in nanometres?
You illuminate a slit with a width of 78.1 µm with a light of wavelength 729 nm and observe the resulting diffraction pattern on a screen that is situated 2.27 m from the slit. What is the width w, in centimeters, of the pattern's central maximum? W = cm
A double-slit interference pattern is created by two narrow slits spaced 0.20 mm apart. The distance between the first and the fifth minimum on a screen 59 cm behind the slits is 6.5 mm. What is the wavelength (in nmnm) of the light used in this experiment?
Consider a light wave passing through a slit and propagating toward a distant screen. Figure P37.53 shows the intensity variation for the pattern on the screen. Give a mathematical argument that more than 90% of the transmitted energy is in the central maximum of the diffraction pattern. Sugges- tion: You are not expected to calculate the precise percent- age, but explain the steps of your reasoning. You may use the identification 1 1 8 Imax asine -3T -27 -T 27 37 A Figure P37.53 ||
Light with wavelength å passes through a narrow slit of width w and is seen on a screen which is located at a distance D in front of the slit. The first minimum of the diffraction pattern is at distanced from the middle of the central maximum. Calculate the wavelength of light if VAD. Give your D=1.3 m, d=1 mm and w = answer in nanometers.

SEE MORE QUESTIONS