The wheels of a wagon can be approximated as the combination of a thin outer hoop of radius rh = 0.315 m and mass 4.89 kg, and two thin crossed rods of mass 7.37 kg each. Imagine replacing the wagon wheels with uniform disks that are ta = 5.88 cm thick, made out of a material with a density of 6450 kg/m³. If the new wheel is to have the same moment of inertia about its center as the old wheel about its center, what should the radius of the disk be? ta rd = 0.169 Incorrect m

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Attempt 1 answer: 0.0768 (wrong) Attempt 2 answer: 0.169 (Wrong)
The wheels of a wagon can be approximated as the combination of a thin outer hoop of radius \( r_h = 0.315 \, \text{m} \) and mass \( 4.89 \, \text{kg} \), and two thin crossed rods of mass \( 7.37 \, \text{kg each} \). Imagine replacing the wagon wheels with uniform disks that are \( t_d = 5.88 \, \text{cm} \) thick, made out of a material with a density of \( 6450 \, \text{kg/m}^3 \). If the new wheel is to have the same moment of inertia about its center as the old wheel about its center, what should the radius of the disk be?

**Illustration Explanation:**

- **Diagram Overview:**
  - On the left, the original wagon wheel is shown. The wheel consists of a thin outer hoop and crossed rods.
  - To the right, the new proposed uniform disk is displayed. The disk has a certain thickness \( t_d = 5.88 \, \text{cm} \).
  
- **Parameters:**
  - \( r_h \): Radius of the hoop.
  - \( r_d \): Radius of the disk (value given as \( 0.169 \, \text{m} \) and marked as incorrect).

This setup is used to determine the equivalent radius \( r_d \) for the disk to match the moment of inertia of the original wheel setup.
Transcribed Image Text:The wheels of a wagon can be approximated as the combination of a thin outer hoop of radius \( r_h = 0.315 \, \text{m} \) and mass \( 4.89 \, \text{kg} \), and two thin crossed rods of mass \( 7.37 \, \text{kg each} \). Imagine replacing the wagon wheels with uniform disks that are \( t_d = 5.88 \, \text{cm} \) thick, made out of a material with a density of \( 6450 \, \text{kg/m}^3 \). If the new wheel is to have the same moment of inertia about its center as the old wheel about its center, what should the radius of the disk be? **Illustration Explanation:** - **Diagram Overview:** - On the left, the original wagon wheel is shown. The wheel consists of a thin outer hoop and crossed rods. - To the right, the new proposed uniform disk is displayed. The disk has a certain thickness \( t_d = 5.88 \, \text{cm} \). - **Parameters:** - \( r_h \): Radius of the hoop. - \( r_d \): Radius of the disk (value given as \( 0.169 \, \text{m} \) and marked as incorrect). This setup is used to determine the equivalent radius \( r_d \) for the disk to match the moment of inertia of the original wheel setup.
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