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The weights of two children sitting at ends A nd B of a seesaw are 84 lb and 64 lb, espectively. Where should a third child sit so hat the resultant of the weights of the three =hildren will pass through C if she weighs (a) 50 lb, (b) 52 lb?

The weights of two children sitting at ends A nd B of a seesaw are 84 lb and 64 lb, espectively. Where should a third child sit so hat the resultant of the weights of the three =hildren will pass through C if she weighs (a) 50 lb, (b) 52 lb?

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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**Problem Description:** The weights of two children sitting at ends \( A \) and \( B \) of a seesaw are 84 lb and 64 lb, respectively. Where should a third child sit so that the resultant of the weights of the three children will pass through \( C \) if she weighs: \( (a) \) 60 lb, \( (b) \) 52 lb? **Diagram Explanation:** The diagram shows a seesaw balanced on a fulcrum, labeled \( C \). There are two children at each end of the seesaw: one at point \( A \) and the other at point \( B \). Each end of the seesaw extends 6 feet from the fulcrum. The seesaw is depicted with the child at \( A \) sitting on the left end, and the child at \( B \) sitting on the right end. **Key Details to Note:** - \( A \): Weight = 84 lb, Distance from fulcrum = 6 ft (left end) - \( B \): Weight = 64 lb, Distance from fulcrum = 6 ft (right end) - Seesaw is balanced at point \( C \) (the fulcrum) - The problem is to determine where a third child, with weights specified in two different scenarios (60 lb and 52 lb), should sit to balance the seesaw such that the resultant force passes through \( C \). In this problem, you need to apply principles of moments and balance, where total clockwise moments should equal total counterclockwise moments to find the position of the third child that ensures equilibrium.
Transcribed Image Text:**Problem Description:** The weights of two children sitting at ends \( A \) and \( B \) of a seesaw are 84 lb and 64 lb, respectively. Where should a third child sit so that the resultant of the weights of the three children will pass through \( C \) if she weighs: \( (a) \) 60 lb, \( (b) \) 52 lb? **Diagram Explanation:** The diagram shows a seesaw balanced on a fulcrum, labeled \( C \). There are two children at each end of the seesaw: one at point \( A \) and the other at point \( B \). Each end of the seesaw extends 6 feet from the fulcrum. The seesaw is depicted with the child at \( A \) sitting on the left end, and the child at \( B \) sitting on the right end. **Key Details to Note:** - \( A \): Weight = 84 lb, Distance from fulcrum = 6 ft (left end) - \( B \): Weight = 64 lb, Distance from fulcrum = 6 ft (right end) - Seesaw is balanced at point \( C \) (the fulcrum) - The problem is to determine where a third child, with weights specified in two different scenarios (60 lb and 52 lb), should sit to balance the seesaw such that the resultant force passes through \( C \). In this problem, you need to apply principles of moments and balance, where total clockwise moments should equal total counterclockwise moments to find the position of the third child that ensures equilibrium.
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