the weight W of a steel ball bearing varies directly with the cube of the bearing's radius r according to the formula W= 4/3 pi(p)(r)^3, where p is the density of the steel. The surface area of a bearing varies directly as the square of its radius because A = 4 pi(r^2) a. Express the weight W of a bearing in terms of its surface area b. Express the bearing's surface area A in terms of its weight. c. For steel, p = 7.85 g/cm^3. What s the surface area of a bearing weighing 0.62 g?
the weight W of a steel ball bearing varies directly with the cube of the bearing's radius r according to the formula W= 4/3 pi(p)(r)^3, where p is the density of the steel. The surface area of a bearing varies directly as the square of its radius because A = 4 pi(r^2) a. Express the weight W of a bearing in terms of its surface area b. Express the bearing's surface area A in terms of its weight. c. For steel, p = 7.85 g/cm^3. What s the surface area of a bearing weighing 0.62 g?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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the weight W of a steel ball bearing varies directly with the cube of the bearing's radius r according to the formula W= 4/3 pi(p)(r)^3, where p is the density of the steel. The surface area of a bearing varies directly as the square of its radius because A = 4 pi(r^2)
a. Express the weight W of a bearing in terms of its surface area
b. Express the bearing's surface area A in terms of its weight.
c. For steel, p = 7.85 g/cm^3. What s the surface area of a bearing weighing 0.62 g?
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