The weight of the leg below the knee is 44.5 N, with the center of gravity located below the knee joint. The leg is being held in this position because of the force M applied by the quadriceps muscle, which is attached 0.100 m below the knee joint (see the drawing). Obtain the magnitude of M. Mi Knee joint 25.0° 0.100 m x cg 0.150 m 30.0°

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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* A person is sitting with one
leg outstretched and stationary,
so that it makes an angle of 30.08 with
the horizontal, as the drawing indicates.

The weight of the leg below the knee is 44.5 N, with the center of gravity
located below the knee joint. The leg is being held in this position because
of the force M applied by the quadriceps muscle, which is attached 0.100 m
below the knee joint (see the drawing). Obtain the magnitude of M.
Mi
Knee joint
25.0°
0.100 m x
cg
0.150 m
30.0°
Transcribed Image Text:The weight of the leg below the knee is 44.5 N, with the center of gravity located below the knee joint. The leg is being held in this position because of the force M applied by the quadriceps muscle, which is attached 0.100 m below the knee joint (see the drawing). Obtain the magnitude of M. Mi Knee joint 25.0° 0.100 m x cg 0.150 m 30.0°
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