The weight of a random person is normally distributed, with a mean of 62 kg and variance of 15 kg2. What is the probability that a random person's height is over 58 kg?Please round your result to two decimal places, and use the z-table. Standard Normal Distrībution Function: (z) =Le-y*/2 dy.00.01020304.05060709.0.5000.5040.5080.5120.5160.5199.5239.5279.5319.5359.1.5398.5438.5478.5517.5557.5596.5636.5675.5714.5753.2.5793.5832.5871.5910.5948.5987.6026.6064.6103.6141.6255.6480.6844.3.6179.6217.6293.6331.6368 .6406.6443.65174.6554.6591.6628.6664.6700.6736.6772.6808.6879.5.6915.6950.6985.7019.7054.7088.71237157.7190.7224.7549.7852.6.7257.7291.7324.7357.7389.7422.7454.7486.7517.7.7580.7611.7642.7673.7704.7734.7764.7794.7823.8.7881.7910.7939.7967.7995.8023.8051.8078.8106.8133.9.8159.8186.8212.8238.8264.8289.8315.8340.836583891.0.8413.8438.8461.8485.8508.8531.8554.8577.859986211.18643.8665.86868708.8729.8749.877087908810.88301.2.8849.8869.8888.8907.892589448962.8980.8997.90151.390329049906690829099.91159131.91479162.91771.4919292079222.9236.9251.9265.92799292.9306.9319944195451.593329345935793709382.9394.9406.941894291.69452946394749484.9495.950595159525.95351.79554.9564957395829591.959996089616.962596331.8.964196499656966496719678968696939699.97061.99713971997269732.9738974497509756.9761.9767209772977897839788.9793.9798.9803980898129817219821982698309834.9838.9842.98469850.9854.9857229861986498689871.9875.9878.98819884.9887.98902.39893989698989901.9904.9906.9909.9911.9913.9916249918992099229925.99279929.99319932.9934993625.9938994099419943.9945.9946.9948.9949.9951.995226.9953.9955995699579960.996399599969.9961.9962.99642799659966.99679968.9970.9971.9972.9973.99742.8.99749975.9976.99779977.9978.9979.9979.99809981299981998299829983.99849984.998599859986.99863.0.998799879987.9988.9988.9989.9989.9989.9990.99903.19990999199919991.9992.9992.9992.9992.9993.9993999399953.299939994.99949994.9994999499959995.99953.3.9995.9995.99969996.9996.9996.99969996.99973.4.999799979997.9997.9997.9997.9997.9997.9997.9998

Answered: Image /qna-images/answer/5c924b38-ec2b-49e4-90bd-802e280de3bd.jpg

The weight of a random person is normally distributed, with a mean of 62 kg and variance of 15 kg2. What is the probability that a random person's height is over 58 kg? Please round your result to two decimal places, and use the z-table.

The weight of a random person is normally distributed, with a mean of 62 kg and variance of 15 kg2. What is the probability that a random person's height is over 58 kg? Please round your result to two decimal places, and use the z-table.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Related questions

Q: The mean weight of an adult is 76 kilograms with a variance of 100. If 142 adults are randomly…

A: Given Mean=mu=76 Variance=sigma^2=100 Standard deviation=sigma=10 n=142

Q: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 6…

A: Solution

Q: Assume that the results are normally distributed. Pedro took an exam in a class in which the mean…

A: The formula for z-score is z = x - μσ where μ is the mean and σ is the standard deviation.…

Q: The weights of newborn baby boys born at a local hospital are believed to have a normal distribution…

A: Given that, Mean = 3915 Variance = 429025

Q: A racing car consumes a mean of 107 gallons of gas per race with the variance of 49. If 46 racing…

A: The following information has been provided: The population mean is μ=107. The sample variance is…

Q: The weights of newborn baby boys born at a local hospital are believed to have a normal distribution…

A: Given that the mean weight is 3915 grams and a variance of 429,025. That is, μ=3915, σ2=429025

Q: The weights of men in their 30s are normally distributed with a mean of 190 pounds and a standard…

A: From the provided information, Population mean (µ) = 190 pounds Population standard deviation (σ) =…

Q: Working in the garden pulling weeds/planting flowers burns an average of 200 calories per hour. If…

A: given data μ=200σ=9normal distribution P(200<x<225)=?

Q: Suppose that the distribution of touchdown passes (in football) is normally distributed with a mean…

Q: Working in the garden pulling weeds/planting flowers burns an average of 200 calories per hour. If…

A: It is given that Mean, μ = 200 Standard deviation, σ = 9 Z-Score, Z = ( X - μ )/σ

Q: Assume thAt scores on a standardized test are known to follow a bell shaped distribution with a mean…

A: L

Q: The test scores are normally distributed with a mean of 78 and a standard deviation of 9. If 39…

A: Obtain the probability that the average score is between 80 and 84. The probability that the average…

Q: The mean height of male college students in a large city is 68 inches and the standard deviation is…

A: Solution

Q: Suppose a variable is normally distributed. What percentage of scores fall between one standard…

Q: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 7…

A: Given information- Mean waiting time, µ = 7 minutes The variance of the waiting time, σ2 = 4 So, the…

Q: The variance of the scores on a skill evaluation test is 123,201 with a mean of 1528 points. If 343…

Q: The average number of pounds of red meat a person consumes each year is 196 with a standard…

A: We are given,μ = 196σ = 22n = 60

Q: The average length of crocodiles in a swamp is 11 feet. If the lengths are normally distributed with…

A: Given: μ = 11 σ = 1.5 Formula Used: Z = X-μσ

Q: A bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean…

A: It is given that the ratings are normally distributed with mean 200 miles and standard deviation 50.

Q: The mean weight of an adult is 62 kilograms with a variance of 144. If 195 adults are randomly…

Q: The weights of college football players are normally distributed with a mean of 193 pounds and a…

A: Mean = 193 Standard deviation = 53

Q: A racing car consumes a mean of 104 gallons of gas per race with a variance of 9. If 50 racing…

Q: The net weight of a can of salmon is a random variable with a mean of 6.21 ounces and a standard…

A: Solution

Q: The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that…

Q: The mean diameter is 84 millimeters and the variance is 16. Find the probability that the diameter…

A: We have to find he probability that the diameter of a selected bearing is greater than 90…

Q: he manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that…

Q: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 7…

A: We have to find given probability.

Q: The mean points obtained in an aptitude examination is 143 points with a variance of 361. What…

A: The population mean is, The population variance is, The population standard deviation is The…

Q: A racing car consumes a mean of 101 gallons of gas per race with a variance of 49. If 43 racing…

A: The probability that the sample mean would differ from the population mean by greater than 2.4…

Q: Brenda has collected data to find that the finishing times for cyclists in a race has a normal…

A: Given the finishing time for cyclists in a race has normal distribution with mean 143 minutes and…

Q: maria has calculated the variance for a set of data and now takes the square root of that value. she…

A: Variance is calculated by taking the summation of squared deviation of observations from their mean…

Q: The green turtle migrates across the Southern Atlantic in the winter, swimming great distances. A…

A: X~N( μ , ?) μ=2200 , ?=625 Z-score =( x - μ )/?

Q: find the probability that the mean time of a sample of 15 Americans who shower will be less than 12…

Q: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 4…

A: Given that μ=4σ=9

Q: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 4…

A: According to the given information in this question We need to find the probability that a person…

Q: A racing car consumes a mean of 103 gallons of gas per race with a variance of 36. If 38 racing…

A: The probability of the sample mean would be greater than 101.5 gallons is 0.9382 and it is obtained…

Q: A given age group's average height is 53 inches, with a standard variation of 4 inches. Determine…

Q: e average height of mall giraffes is 16.3 feet. If the heights are normally distributed with a…

A: Given data,Mean μ=16.3sd σ=3.2P(15<X<20)=?

Question

The weight of a random person is normally distributed, with a mean of 62 kg and variance of 15 kg².

What is the probability that a random person's height is over 58 kg?

Please round your result to two decimal places, and use the z-table.

Standard Normal Distrībution Function: (z) =Le-y*/2 dy
.00
.01
02
03
04
.05
06
07
09
.0
.5000
.5040
.5080
.5120
.5160
.5199
.5239
.5279
.5319
.5359
.1
.5398
.5438
.5478
.5517
.5557
.5596
.5636
.5675
.5714
.5753
.2
.5793
.5832
.5871
.5910
.5948
.5987
.6026
.6064
.6103
.6141
.6255
.6480
.6844
.3
.6179
.6217
.6293
.6331
.6368 .6406
.6443
.6517
4
.6554
.6591
.6628
.6664
.6700
.6736
.6772
.6808
.6879
.5
.6915
.6950
.6985
.7019
.7054
.7088
.7123
7157
.7190
.7224
.7549
.7852
.6
.7257
.7291
.7324
.7357
.7389
.7422
.7454
.7486
.7517
.7
.7580
.7611
.7642
.7673
.7704
.7734
.7764
.7794
.7823
.8
.7881
.7910
.7939
.7967
.7995
.8023
.8051
.8078
.8106
.8133
.9
.8159
.8186
.8212
.8238
.8264
.8289
.8315
.8340
.8365
8389
1.0
.8413
.8438
.8461
.8485
.8508
.8531
.8554
.8577
.8599
8621
1.1
8643
.8665
.8686
8708
.8729
.8749
.8770
8790
8810
.8830
1.2
.8849
.8869
.8888
.8907
.8925
8944
8962
.8980
.8997
.9015
1.3
9032
9049
9066
9082
9099
.9115
9131
.9147
9162
.9177
1.4
9192
9207
9222
.9236
.9251
.9265
.9279
9292
.9306
.9319
9441
9545
1.5
9332
9345
9357
9370
9382
.9394
.9406
.9418
9429
1.6
9452
9463
9474
9484
.9495
.9505
9515
9525
.9535
1.7
9554
.9564
9573
9582
9591
.9599
9608
9616
.9625
9633
1.8
.9641
9649
9656
9664
9671
9678
9686
9693
9699
.9706
1.9
9713
9719
9726
9732
.9738
9744
9750
9756
.9761
.9767
20
9772
9778
9783
9788
.9793
.9798
.9803
9808
9812
9817
21
9821
9826
9830
9834
.9838
.9842
.9846
9850
.9854
.9857
22
9861
9864
9868
9871
.9875
.9878
.9881
9884
.9887
.9890
2.3
9893
9896
9898
9901
.9904
.9906
.9909
.9911
.9913
.9916
24
9918
9920
9922
9925
.9927
9929
.9931
9932
.9934
9936
25
.9938
9940
9941
9943
.9945
.9946
.9948
.9949
.9951
.9952
26
.9953
.9955
9956
9957
9960
.9963
9959
9969
.9961
.9962
.9964
27
9965
9966
.9967
9968
.9970
.9971
.9972
.9973
.9974
2.8
.9974
9975
.9976
.9977
9977
.9978
.9979
.9979
.9980
9981
29
9981
9982
9982
9983
.9984
9984
.9985
9985
9986
.9986
3.0
.9987
9987
9987
.9988
.9988
.9989
.9989
.9989
.9990
.9990
3.1
9990
9991
9991
9991
.9992
.9992
.9992
.9992
.9993
.9993
9993
9995
3.2
9993
9994
.9994
9994
.9994
9994
9995
9995
.9995
3.3
.9995
.9995
.9996
9996
.9996
.9996
.9996
9996
.9997
3.4
.9997
9997
9997
.9997
.9997
.9997
.9997
.9997
.9997
.9998

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

Christopher has collected data to find that the total snowfall per year in Laytonville has a normal distribution. What is the probability that in a randomly selected year, the snowfall was greater than 53 inches if the mean is 92 inches and the standard deviation is 13 inches? Use the empirical rule.
A bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviation of 50. If an applicant is randomly selected, find the probability that the applicant's rating will be between 205 and 275. (Round your answer to 4 decimal places.)
The time spent waiting in the line is approximately normally distributed. The mean waiting time is 6 minutes and the variance of the waiting time is 1. Find the probability that a person will walt for less than 7 minutes. Round your answer to four decimal places. Answer esc If you would like to look up the value in a table, select the table you want to view, then either click the cell at the intersection of the row and column or use the arrow keys to find the appropriate cell in the table and select it using the Space key. 1 hp angle. q a Z F @ 2 W S 320 3 e d C $ 4 r f % 5 V t g Normal Table - to-z Normal Table - to z 6 O Oll b y hp h & 7 O n u J - * 8 N O i m 9 k * O : Tables ctrl Keypa Keyboard Shortc Submit Answer { D + = ? Oct 27 11 } 5:21 8 back 1 USE YOUR SMARTIN Reviews - Videog Spass Sun
The weight of garbage produced per household per week has an average value of approximately 9.3 pounds. The standard deviation of garbage per household per week has been measured to be 2.7 pounds. You have a garbage hauling company and need to know the probability of hauling heavy loads of garbage. How would you calculate the probability that your company will be hauling garbage loads greater than 12 pounds per household during a weekly pick-up? probability. Set up your calculation correctly. You DO NOT need to calculate the
A normally distributed random variable has a mean of 449. If a score of 433 lies two standard deviations below the mean, find the variance of X.
male beluga whales have a mean weight of 1980 pounds with a standard deviation of 220 pounds. Assume that weight are normally distributed.Find the probability that an SRS of 10 Belugas has a mean weight between 1900 and 2100 pounds.
The mean weight of an adult is 71 kilograms with a variance of 100. If 181 adults are randomly selected, what is the probability that the sample mean would differ from the population mean by less than 1.2 kilograms? Round your answer to four decimal places.
The weights of college football players are normally distributed with a mean of 191 pounds and a standard deviation of 49 pounds. If a college football player is randomly selected, find the probability that he weighs between 205 and 224 pounds
The time spent waiting in the line is approximately normally distributed. The mean waiting time is 5 minutes and the variance of the waiting time is 1. Find the probability that a person will wait for more than 3 minutes. Round your answer to four decimal places.