The weight of a pony standing still on Earth is 1025 N. Select all the answers that are correct. (I used 9.8m/s/s for all calculations.) [mark all correct answers] a. mass of pony on Earth = 104.6 kg b. weight of pony on Earth = 104.6 N c. weight of pony on the moon = 170.8 N d. mass of pony on the moon 170.8 kg e. amount of normal force pushing up on the pony on Earth = 1025 N f. amount of normal force pushing up on the pony on the moon = 1025 N g. the force of attraction between the pony and the Earth = 1025 N
The weight of a pony standing still on Earth is 1025 N. Select all the answers that are correct. (I used 9.8m/s/s for all calculations.) [mark all correct answers] a. mass of pony on Earth = 104.6 kg b. weight of pony on Earth = 104.6 N c. weight of pony on the moon = 170.8 N d. mass of pony on the moon 170.8 kg e. amount of normal force pushing up on the pony on Earth = 1025 N f. amount of normal force pushing up on the pony on the moon = 1025 N g. the force of attraction between the pony and the Earth = 1025 N
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![The weight of a pony standing still on Earth is 1025 N.
Select all the answers that are correct.
*(I used 9.8 m/s² for all calculations.)*
[Mark all correct answers]
- a. mass of pony on Earth = 104.6 kg
- b. weight of pony on Earth = 104.6 N
- c. weight of pony on the moon = 170.8 N
- d. mass of pony on the moon = 170.8 kg
- e. amount of normal force pushing up on the pony on Earth = 1025 N
- f. amount of normal force pushing up on the pony on the moon = 1025 N
- g. the force of attraction between the pony and the Earth = 1025 N
### Analysis
**Correct Answer Explanation:**
1. **a. mass of pony on Earth = 104.6 kg**
- The weight (W) of an object is given by \( W = mg \), where \( m \) is the mass and \( g \) is the gravitational acceleration (9.8 m/s² on Earth). Given that \( W = 1025 \, \text{N} \), we calculate:
\[ m = \frac{W}{g} = \frac{1025}{9.8} \approx 104.6 \, \text{kg} \]
2. **e. amount of normal force pushing up on the pony on Earth = 1025 N**
- On Earth, an object at rest experiences a normal force equal in magnitude to its weight due to gravity, which is 1025 N.
3. **g. the force of attraction between the pony and the Earth = 1025 N**
- This is another expression for the weight of the pony, which is the gravitational force acting on it.
### Incorrect Answers Explanation:
- **b. weight of pony on Earth = 104.6 N**
- Incorrect since the weight is given as 1025 N, not 104.6 N.
- **c. weight of pony on the moon = 170.8 N**
- Incorrect due to using wrong gravitational force calculation. Moon's gravity is about 1/6th of Earth's, so use \( g_{\text{moon}} \approx 1.63 \, \text{m/s²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3fe4e0d9-a441-4076-9243-8e98c4a90bfe%2Fe215387a-289c-4d7e-92d1-fb3a47469d64%2Fjskkk4p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The weight of a pony standing still on Earth is 1025 N.
Select all the answers that are correct.
*(I used 9.8 m/s² for all calculations.)*
[Mark all correct answers]
- a. mass of pony on Earth = 104.6 kg
- b. weight of pony on Earth = 104.6 N
- c. weight of pony on the moon = 170.8 N
- d. mass of pony on the moon = 170.8 kg
- e. amount of normal force pushing up on the pony on Earth = 1025 N
- f. amount of normal force pushing up on the pony on the moon = 1025 N
- g. the force of attraction between the pony and the Earth = 1025 N
### Analysis
**Correct Answer Explanation:**
1. **a. mass of pony on Earth = 104.6 kg**
- The weight (W) of an object is given by \( W = mg \), where \( m \) is the mass and \( g \) is the gravitational acceleration (9.8 m/s² on Earth). Given that \( W = 1025 \, \text{N} \), we calculate:
\[ m = \frac{W}{g} = \frac{1025}{9.8} \approx 104.6 \, \text{kg} \]
2. **e. amount of normal force pushing up on the pony on Earth = 1025 N**
- On Earth, an object at rest experiences a normal force equal in magnitude to its weight due to gravity, which is 1025 N.
3. **g. the force of attraction between the pony and the Earth = 1025 N**
- This is another expression for the weight of the pony, which is the gravitational force acting on it.
### Incorrect Answers Explanation:
- **b. weight of pony on Earth = 104.6 N**
- Incorrect since the weight is given as 1025 N, not 104.6 N.
- **c. weight of pony on the moon = 170.8 N**
- Incorrect due to using wrong gravitational force calculation. Moon's gravity is about 1/6th of Earth's, so use \( g_{\text{moon}} \approx 1.63 \, \text{m/s²
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