The weight of a pony standing still on Earth is 1025 N. Select all the answers that are correct. (I used 9.8m/s/s for all calculations.) [mark all correct answers] a. mass of pony on Earth = 104.6 kg b. weight of pony on Earth = 104.6 N c. weight of pony on the moon = 170.8 N d. mass of pony on the moon 170.8 kg e. amount of normal force pushing up on the pony on Earth = 1025 N f. amount of normal force pushing up on the pony on the moon = 1025 N g. the force of attraction between the pony and the Earth = 1025 N

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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The weight of a pony standing still on Earth is 1025 N.

Select all the answers that are correct.

*(I used 9.8 m/s² for all calculations.)*

[Mark all correct answers]

- a. mass of pony on Earth = 104.6 kg
- b. weight of pony on Earth = 104.6 N
- c. weight of pony on the moon = 170.8 N
- d. mass of pony on the moon = 170.8 kg
- e. amount of normal force pushing up on the pony on Earth = 1025 N
- f. amount of normal force pushing up on the pony on the moon = 1025 N
- g. the force of attraction between the pony and the Earth = 1025 N

### Analysis

**Correct Answer Explanation:**

1. **a. mass of pony on Earth = 104.6 kg**
   - The weight (W) of an object is given by \( W = mg \), where \( m \) is the mass and \( g \) is the gravitational acceleration (9.8 m/s² on Earth). Given that \( W = 1025 \, \text{N} \), we calculate: 
     \[ m = \frac{W}{g} = \frac{1025}{9.8} \approx 104.6 \, \text{kg} \]

2. **e. amount of normal force pushing up on the pony on Earth = 1025 N**
   - On Earth, an object at rest experiences a normal force equal in magnitude to its weight due to gravity, which is 1025 N.

3. **g. the force of attraction between the pony and the Earth = 1025 N**
   - This is another expression for the weight of the pony, which is the gravitational force acting on it.

### Incorrect Answers Explanation:

- **b. weight of pony on Earth = 104.6 N** 
  - Incorrect since the weight is given as 1025 N, not 104.6 N.
  
- **c. weight of pony on the moon = 170.8 N**
  - Incorrect due to using wrong gravitational force calculation. Moon's gravity is about 1/6th of Earth's, so use \( g_{\text{moon}} \approx 1.63 \, \text{m/s²
Transcribed Image Text:The weight of a pony standing still on Earth is 1025 N. Select all the answers that are correct. *(I used 9.8 m/s² for all calculations.)* [Mark all correct answers] - a. mass of pony on Earth = 104.6 kg - b. weight of pony on Earth = 104.6 N - c. weight of pony on the moon = 170.8 N - d. mass of pony on the moon = 170.8 kg - e. amount of normal force pushing up on the pony on Earth = 1025 N - f. amount of normal force pushing up on the pony on the moon = 1025 N - g. the force of attraction between the pony and the Earth = 1025 N ### Analysis **Correct Answer Explanation:** 1. **a. mass of pony on Earth = 104.6 kg** - The weight (W) of an object is given by \( W = mg \), where \( m \) is the mass and \( g \) is the gravitational acceleration (9.8 m/s² on Earth). Given that \( W = 1025 \, \text{N} \), we calculate: \[ m = \frac{W}{g} = \frac{1025}{9.8} \approx 104.6 \, \text{kg} \] 2. **e. amount of normal force pushing up on the pony on Earth = 1025 N** - On Earth, an object at rest experiences a normal force equal in magnitude to its weight due to gravity, which is 1025 N. 3. **g. the force of attraction between the pony and the Earth = 1025 N** - This is another expression for the weight of the pony, which is the gravitational force acting on it. ### Incorrect Answers Explanation: - **b. weight of pony on Earth = 104.6 N** - Incorrect since the weight is given as 1025 N, not 104.6 N. - **c. weight of pony on the moon = 170.8 N** - Incorrect due to using wrong gravitational force calculation. Moon's gravity is about 1/6th of Earth's, so use \( g_{\text{moon}} \approx 1.63 \, \text{m/s²
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