The weekly demand for propane gas (in 1000s of gallons) from a particular facility is an rv X with the following pdf 1sxS 2 f(x) otherwise

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Using the screenshot, please obtain an expression for the (100p)th percentile.

The weekly demand for propane gas (in 1000s of gallons) from a particular facility is a random variable \( X \) with the following probability density function (pdf):

\[
f(x) = 
\begin{cases} 
2 \left( 1 - \frac{1}{x^2} \right) & \text{for } 1 \leq x \leq 2 \\
0 & \text{otherwise}
\end{cases}
\] 

- **Explanation**: The function \( f(x) \) specifies how the probability is distributed across the different values of demand (in 1000s of gallons). For values of \( x \) between 1 and 2, the function \( f(x) \) is defined by the formula \( 2 \left( 1 - \frac{1}{x^2} \right) \). For any other value of \( x \), the probability is 0. This distribution shows how likely different levels of demand are within the specified range. The graph of this function would have a curve starting at \( x = 1 \), ending at \( x = 2 \), and be flat (at \( f(x) = 0 \)) outside of this interval.
Transcribed Image Text:The weekly demand for propane gas (in 1000s of gallons) from a particular facility is a random variable \( X \) with the following probability density function (pdf): \[ f(x) = \begin{cases} 2 \left( 1 - \frac{1}{x^2} \right) & \text{for } 1 \leq x \leq 2 \\ 0 & \text{otherwise} \end{cases} \] - **Explanation**: The function \( f(x) \) specifies how the probability is distributed across the different values of demand (in 1000s of gallons). For values of \( x \) between 1 and 2, the function \( f(x) \) is defined by the formula \( 2 \left( 1 - \frac{1}{x^2} \right) \). For any other value of \( x \), the probability is 0. This distribution shows how likely different levels of demand are within the specified range. The graph of this function would have a curve starting at \( x = 1 \), ending at \( x = 2 \), and be flat (at \( f(x) = 0 \)) outside of this interval.
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