The wavelength of a wave that is the natural frequency (or first harmonic) for a string is 1.4 m. How long is the string? Your answer: 0.7 m 1.4 m 2.0 m 2.8 m

College Physics
11th Edition
ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Physics Problem: Calculating the Length of a String

#### Question:
The wavelength of a wave that is the natural frequency (or first harmonic) for a string is 1.4 m. How long is the string?

#### Your answer:
- ☐ 0.7 m
- ☐ 1.4 m
- ☐ 2.0 m
- ☐ 2.8 m

#### Explanation:
In a string fixed at both ends, the first harmonic (or the fundamental frequency) has a wavelength that is twice the length of the string. This is because there is one full wave (one wavelength) fitting over two times the length of the string.

**Given:**
- Wavelength (λ) = 1.4 m

**To find:**
- Length of the string (L)

For the first harmonic:
\[ \lambda = 2 \times L \]

So, the length of the string:
\[ L = \frac{\lambda}{2} \]
\[ L = \frac{1.4 \, \text{m}}{2} \]
\[ L = 0.7 \, \text{m} \]

#### Correct answer:
- ☑ 0.7 m
Transcribed Image Text:### Physics Problem: Calculating the Length of a String #### Question: The wavelength of a wave that is the natural frequency (or first harmonic) for a string is 1.4 m. How long is the string? #### Your answer: - ☐ 0.7 m - ☐ 1.4 m - ☐ 2.0 m - ☐ 2.8 m #### Explanation: In a string fixed at both ends, the first harmonic (or the fundamental frequency) has a wavelength that is twice the length of the string. This is because there is one full wave (one wavelength) fitting over two times the length of the string. **Given:** - Wavelength (λ) = 1.4 m **To find:** - Length of the string (L) For the first harmonic: \[ \lambda = 2 \times L \] So, the length of the string: \[ L = \frac{\lambda}{2} \] \[ L = \frac{1.4 \, \text{m}}{2} \] \[ L = 0.7 \, \text{m} \] #### Correct answer: - ☑ 0.7 m
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