The wave functions of two sinusoidal waves traveling in the same medium are: y1 = 0.7 sin (–0, 25nt + 4nx) y2 = 0.7 sin (-0, 25nt + 4nx + t/2) The expression of the resultant wave is: A-y = 0.35 sin (-0, 25nt + 4nx + n/4) B- y = 1.4sin (4nx)Cos(-0, 25nt + n/2) C- y = 0.7 sin (-0,25nt + 4nx + n/2) D- y = 1.4sin (4nx)Cos(-0,25at) E - y = 1.4sin (4nx)Cos(-0, 25nt) A В C O E
The wave functions of two sinusoidal waves traveling in the same medium are: y1 = 0.7 sin (–0, 25nt + 4nx) y2 = 0.7 sin (-0, 25nt + 4nx + t/2) The expression of the resultant wave is: A-y = 0.35 sin (-0, 25nt + 4nx + n/4) B- y = 1.4sin (4nx)Cos(-0, 25nt + n/2) C- y = 0.7 sin (-0,25nt + 4nx + n/2) D- y = 1.4sin (4nx)Cos(-0,25at) E - y = 1.4sin (4nx)Cos(-0, 25nt) A В C O E
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![The wave functions of two sinusoidal waves traveling in the same
medium are:
y1 = 0.7 sin (-0, 25nt + 4nx)
y2 = 0.7 sin (-0, 25nt + 4nx + t/2)
The expression of the resultant wave is:
A-y = 0.35 sin (–0,25nt + 4nx + nt/4)
B- y = 1.4sin (4nx)Cos(-0, 25nt + t/2)
C-y 0.7 sin (-0, 25πι + 4πx + π/2)
D- y = 1.4sin (4nx)Cos(-0, 25nt)
E - y = 1.4sin (4nx)Cos(-0, 25nt)
A
В
D
O E](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F82a456b4-5015-41a2-91ef-14aac2761ec1%2F7f1890c2-7d24-454e-97d4-4caa7158e24e%2Fll0oxpi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The wave functions of two sinusoidal waves traveling in the same
medium are:
y1 = 0.7 sin (-0, 25nt + 4nx)
y2 = 0.7 sin (-0, 25nt + 4nx + t/2)
The expression of the resultant wave is:
A-y = 0.35 sin (–0,25nt + 4nx + nt/4)
B- y = 1.4sin (4nx)Cos(-0, 25nt + t/2)
C-y 0.7 sin (-0, 25πι + 4πx + π/2)
D- y = 1.4sin (4nx)Cos(-0, 25nt)
E - y = 1.4sin (4nx)Cos(-0, 25nt)
A
В
D
O E
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