The wave function of an electron confined in a one-dimensional infinite potential well of width Lis ᎡᏆ . &n(x) = (272), where n is a positive integer. If the electron is in the n = 5 state: i) Calculate the probability of finding the electron between x = Land x = L. ii) Calculate the probability of finding the electron in an interval of width 0.04L located at x = L. sin(
The wave function of an electron confined in a one-dimensional infinite potential well of width Lis ᎡᏆ . &n(x) = (272), where n is a positive integer. If the electron is in the n = 5 state: i) Calculate the probability of finding the electron between x = Land x = L. ii) Calculate the probability of finding the electron in an interval of width 0.04L located at x = L. sin(
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![The wave function of an electron confined in a one-dimensional infinite potential well of
width L is
$₁₂(x)=√ √ √ ²/1₁ sin( -),
2 NTX
L
where n is a positive integer. If the electron is in the n = 5 state:
i) Calculate the probability of finding the electron between x = L and x = L.
ii)
Calculate the probability of finding the electron in an interval of width 0.04L located at
= = }L.
x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8b15f582-90bf-4248-8ad2-3f9040e9bb5a%2Face0facf-cea4-4903-b402-bf4e780cd657%2F6ejj81v_processed.png&w=3840&q=75)
Transcribed Image Text:The wave function of an electron confined in a one-dimensional infinite potential well of
width L is
$₁₂(x)=√ √ √ ²/1₁ sin( -),
2 NTX
L
where n is a positive integer. If the electron is in the n = 5 state:
i) Calculate the probability of finding the electron between x = L and x = L.
ii)
Calculate the probability of finding the electron in an interval of width 0.04L located at
= = }L.
x
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