The wall of a cold room consists of a layer of cork sandwiched between outer and inner walls of wood, the wood walls being each 30 mm thick. The inside atmosphere of the room is maintained at -20 °C when the external atmospheric temperature is 25 °C, the heat loss through the wall is 42 W/m2. Taking the thermal conductivity of wood and cork as 0.20 W/m-K and 0.05 W/m-K respectively, and the rate of heat transfer between each exposed wood surface and their respective atmospheres as 15 W/m2-K, calculate the thickness of the cork. (mm)
The wall of a cold room consists of a layer of cork sandwiched between outer and inner walls of wood, the wood walls being each 30 mm thick. The inside atmosphere of the room is maintained at -20 °C when the external atmospheric temperature is 25 °C, the heat loss through the wall is 42 W/m2. Taking the thermal conductivity of wood and cork as 0.20 W/m-K and 0.05 W/m-K respectively, and the rate of heat transfer between each exposed wood surface and their respective atmospheres as 15 W/m2-K, calculate the thickness of the cork. (mm)
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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2. The wall of a cold room consists of a layer of cork sandwiched between outer and inner walls of wood, the wood walls being each 30 mm thick. The inside atmosphere of the room is maintained at -20 °C when the external atmospheric temperature is 25 °C, the heat loss through the wall is 42 W/m2. Taking the thermal conductivity of wood and cork as 0.20 W/m-K and 0.05 W/m-K respectively, and the rate of heat transfer between each exposed wood surface and their respective atmospheres as 15 W/m2-K, calculate the thickness of the cork. (mm)
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