The waiting line at a popular bakery shop can be quite long. Suppose that the waiting time in minutes has probability density functionf(x) = 0.2-e02x. Determine the following:(a) F(x).O F(x) = 10.2.x-0.2.xO F(x) = 1 + e-02O F(x) = 1-e-0.2-xF(x) = 1 + e02-x(b) Probability that a customer waits more than 22 minutes:Round your answer to three decimal places (e.g. 0.987).P = i(c) Probability that a customer waits less than 8 minutes:Round your answer to three decimal places (e.g. 0.987).P = i

Answered: Image /qna-images/answer/aeafcdd0-faef-4fb0-b6d2-76b94d1c64fe.jpg

Answered: The waiting line at a popular bakery…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Let X denote the vibratory stress (psi) on a wind turbine blade at a particular wind speed in a wind tunnel. Suppose that X has the following probability density function (called the Rayleigh probability density function). (x/0²) e-x²/(20²) x > 0 f(x) = 10 otherwise (a) If = 108, find the probability that the vibratory stress is between 82 and 361. (b) If = 108, then 92% of the time the vibratory stress is greater than what value?
(f(x) is a probability density function?(= 0.111 ( 0 Q4/ the value of the constant which makes the function 3>x>0 0.w B) and 0.321 (1 c) 0.5
Consider the following exponential probability density function. f(x) = 1 5 e−x/5 for x ≥ 0 (a) Write the formula for P(x ≤ x0). 1−E−(X5) (b) Find P(x ≤ 4). (Round your answer to four decimal places.) (c) Find P(x ≥ 5). (Round your answer to four decimal places.) (d) Find P(x ≤ 6). (Round your answer to four decimal places.) (e) Find P(4 ≤ x ≤ 6). (Round your answer to four decimal places.)
1. Consider the two functions ƒ(x) = C(2x − x³), g(x) = C(2x − x²), 0 < x < 2. (1) Could f be a probability density function? If so, determine C. If not, explain the reason that why f is not a probability density function. 0 < x < 2, (2) Could g be a probability density function? If so, determine C. If not, explain the reason that why g is not a probability density function.
A continuous random variable has the probability density function of f(x)=0.0118x and the interval of [O 13]. What is the probability that this variable has a value between 1 and 2? Answer: A continuous random variable has the probability density function of f(x)=0.0118x and the interval of [O 13]. What is the cumulative distribution function for the value of 3? Answer:
For what value of c is the function f(x) = {c/x³ if x ≥ 1 {gx3 otherwise a probability density function?
While taking a walk along the road where you live, you accidentally drop your glove, but you don't know where. The probability density p(x) for having dropped the glove a kilometers from home (along the road) is p(x) = 2e-2 for x ≥ 0 a. What is the probability that you dropped it within 1 kilometer of home? I b. At what distance y from home is the probability that you dropped it within y km of home equal to 0.95? km <-|
6. Roughly, speaking, we can use probability density functions to model the likelihood of an event occurring. Formally, a probability density function on (-x, o0) is a function f such that f(r) 20 and (2) = = 1. (a) Determine which of the following functions are probability density functions on the (-x0, 00). fr-1 00 (b) We can also use probability density functions to find the erpected value of the outcomes of the event - if we repeated a probability experiment many times, the expected value will equal the average of the outcomes of the experiment. (e.g. rf(x) dr yields the expected value for a density f(r) with domain on the real numbers.) Find the expected value for one of the valid probability densities above.
Solve it
Şe x² f(x)=cis a probability density function? 0.111 (2 c) 0.5 /The value of the constant, which makes the function 3 >> 00w father 0.321 (
Consider the probability density function f(x) = 1.5x² for -1 ≤x≤ 1. What is P(X > 0)? O a. 0 b. 0.125 c. 0.25 O d. 0.5

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