The volumetric analysis of a mixture of gases is 30 percent oxygen, 40 percent nitrogen, 10 percent carbon dioxide, and 20 percent methane. Calculate the apparent specific heats and molecular weight of this mixture of gases. The universal gas constant is Ru= 8.314 kJ/kmol-K. Use the table containing the molar mass, gas constant, and critical-point properties and the table containing the ideal-gas specific heats of various common gases. The apparent molecular weight of this mixture of gases is [ The constant-pressure specific heat of the mixture is The constant-volume specific heat of the mixture is kg/kmol. kJ/kg-K. kJ/kg-K.

The volumetric analysis of a mixture of gases is 30 percent oxygen, 40 percent nitrogen, 10 percent carbon dioxide, and 20 percent methane. Calculate the apparent specific heats and molecular weight of this mixture of gases. The universal gas constant is Ru= 8.314 kJ/kmol-K. Use the table containing the molar mass, gas constant, and critical-point properties and the table containing the ideal-gas specific heats of various common gases. The apparent molecular weight of this mixture of gases is [ The constant-pressure specific heat of the mixture is The constant-volume specific heat of the mixture is kg/kmol. kJ/kg-K. kJ/kg-K.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Properties of Pure Substances

A substance with fixed chemical composition throughout is called a pure substance like water, air, and nitrogen. A pure substance does not have to be a single element or compound. A mixture of two or more phases of a pure substance is also a pure substance as long as the chemical composition is the same for all phases. These substances mainly have a constant/ uniform composition. The substances also have fixed boiling and melting points. A pure substance takes part in a chemical reaction to form predictable products.

Question

Problem 13.033 Specific Heat and Molecular Weight
The volumetric analysis of a mixture of gases is 30 percent oxygen, 40 percent nitrogen, 10 percent carbon dioxide, and 20 percent
methane. Calculate the apparent specific heats and molecular weight of this mixture of gases. The universal gas constant is Ru = 8.314
kJ/kmol-K. Use the table containing the molar mass, gas constant, and critical-point properties and the table containing the ideal-gas
specific heats of various common gases.
The apparent molecular weight of this mixture of gases is
The constant-pressure specific heat of the mixture is
The constant-volume specific heat of the mixture is
kg/kmol.
kJ/kg-K.
kJ/kg-K.

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