The volume of water needed to dissolve 0.0694 grams of lead fluoride is ______ L. Assume no volume change upon addition of the solid. (Ksp = 3.7 x 10-8)

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  1. The volume of water needed to dissolve 0.0694 grams of lead fluoride is ______ L. Assume no volume change upon addition of the solid. (Ksp = 3.7 x 10-8)
  2. The attached photos is an example of how to solve the problem 
xL.
The volume of water needed to dissolve 0.0700 grams of lead sulfate is 183x10^-8
Assume no volume change upon addition of the solid.
Incorrect
STEP 1 Determine the number of moles of PBSO4(s) that can dissolve in ONE liter:
Let 's' = number of moles per liter that dissolve.
%3D
PBSO4 (s)
= Pb2+ (aq) + SO,²- (aq)
Initial
some
Change
+ S
Equilibrium
some
+ s
+ s
STEP 2 Set up the Ksp expression and solve for s:
Ksp =[Pb2+] [So,2] = (s)(s) = s? = 1.8×108 (from the table)
1.34x104 moles PbSO4
Previous.
Next
1/2
Transcribed Image Text:xL. The volume of water needed to dissolve 0.0700 grams of lead sulfate is 183x10^-8 Assume no volume change upon addition of the solid. Incorrect STEP 1 Determine the number of moles of PBSO4(s) that can dissolve in ONE liter: Let 's' = number of moles per liter that dissolve. %3D PBSO4 (s) = Pb2+ (aq) + SO,²- (aq) Initial some Change + S Equilibrium some + s + s STEP 2 Set up the Ksp expression and solve for s: Ksp =[Pb2+] [So,2] = (s)(s) = s? = 1.8×108 (from the table) 1.34x104 moles PbSO4 Previous. Next 1/2
1.34x10 4 moles PbSO4
Ksp
1/2
1.34x10 4 M =
S =
%3D
L solution
We'll carry 3 significant figures and round to 2 at the end.
STEP 3 Determine the moles of PbSO, to dissolve:
1 mol PbS04
0.0700 g PbSO4x
2.31×101 moles PbSO4
303.3 g PbS04
STEP 4 Determine the volume needed:
1 L solution
V = 2.31x104 moles PbSO4
1.7 L solution needed
1.34×10 4 mol PbSO4
Transcribed Image Text:1.34x10 4 moles PbSO4 Ksp 1/2 1.34x10 4 M = S = %3D L solution We'll carry 3 significant figures and round to 2 at the end. STEP 3 Determine the moles of PbSO, to dissolve: 1 mol PbS04 0.0700 g PbSO4x 2.31×101 moles PbSO4 303.3 g PbS04 STEP 4 Determine the volume needed: 1 L solution V = 2.31x104 moles PbSO4 1.7 L solution needed 1.34×10 4 mol PbSO4
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