The volume of water (in liters) in a reservoir after t hours is given by the function V(t) for 0 < t < 10. The graph of the derivative V'(t) is shown below. V'(t) 2 6 -2 -4 After 10 hours, the volume of water in the tank was 51. What was the volume of water in the at t = 0? (Hint: Note that there was more water at the start than at the end.)

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The relation between two quantities which displays how much greater one quantity is than another is called ratio.

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The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as: