The volume of the solid enclosed above by p = 5 and below by p = a/6 isSelect one or more:125O a. (2 – V3)O b. 1 (2 + v3)ac. (2 – võ)aO d. None of the other options125e.(2 + v6)z

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Answered: The volume of the solid enclosed above…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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What is the area of a square whose side measures (2v3 - V5) inches? A. (17 – 4 V15) in² C. (12 – 4 V15) in B (17 + 4 V15) in² D. (12 + 4 V15) in? Give the quotient of: V20 А. 2 С. В 2 D. 2 Find the sum, where x>0 and simplify: 4x2y4 + V24x3+ y²V81x2 А. 11ху? B. 11xy + 3x V3 C. 11xy + 2×V3 D. 11xy-2x V3 Determine the value of m in 5Vm- 2 = 18. В. 8 A. 4 С. 16 D. 32 For what value of x will make the equation V3x + 2 = Vx + 10 be equal? А. 2 В. 3 С. 4 D. 5
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Mac is about to sue his contractor who promised to install a water tank that holds 590 gallons of water. Mac knows that 590 gallons is the capacity of a tank that holds 79 cubic feet. The cylindrical tank has a radius of 3 feet and height of 2 feet 8 inches. Does the evidence indicate Mac can win the case against the contractor if it goes to court? Does the evidence indicate Mac can win the case against the contractor if it goes to court? Select the correct choice below and fill in the answer box within your choice. (Round to the nearest whole number as needed.) No, the water tank is about Yes, the water tank is about No, the water tank is about Yes, the water tank is about cubic feet too small. cubic feet too large. cubic feet too large. cubic feet too small.
Mr Orlowski is filling his fish tank using a cylindrical can with diameter of 10cm and has a height of30cm. In order to put the top on the tank, Mr Orlowski must leave at least 10cm of room at the top ofthe tank. How many full cylindrical cans of water can he put into the tank, if the tank is 1.75m by 2mand has a height of 1.5m? see image attached
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20. Write an expression för the volume of the solid in terms of x. a. V = ar²h b. V = {wh 2x 3x 8x 5x 2x

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The volume of the solid enclosed above by p = 5 and below by ø = x16 is Select one or more: O a. (2 – V3)a O b. 5 (2 + v3)a O c. 15 (2 – v6)a O d. None of the other options O e. 125 (2 + v6) е.