The volume of the right circular cylinder with a base of radius 4 in the ry-plane and height 5 is 5 27 c4 (a) I drdedz. (b) rdrdodz . drdOdz . Jo Jo The volume of the region inside the cone o = t/4 for 0

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**The Volume of Geometric Shapes Using Integration**

1. **Volume of the Right Circular Cylinder**

   To find the volume of a right circular cylinder with a base of radius 4 in the xy-plane and height 5, evaluate the following integrals:

   - **Option (a):**
     \[
     \int_0^5 \int_0^{2\pi} \int_0^4 dr\,d\theta\,dz
     \]

   - **Option (b):**
     \[
     \int_0^5 \int_0^{2\pi} r\,dr\,d\theta\,dz
     \]

   - **Option (c):**
     \[
     \int_0^5 \int_0^{2\pi} \int_0^2 dr\,d\theta\,dz
     \]

2. **Volume Inside the Cone \(\phi = \pi/4\), \(0 \leq z \leq 4\)**

   To find the volume of the region inside the cone where \(\phi = \pi/4\) and \(0 \leq z \leq 4\), evaluate these integrals:

   - **Option (a):**
     \[
     \int_0^{2\pi} \int_0^{\pi/4} \int_0^{4\sqrt{2}} \rho\,d\rho\,d\phi\,d\theta
     \]

   - **Option (b):**
     \[
     \int_0^{2\pi} \int_0^{\pi/4} \int_0^4 \rho^2 \sin\phi\,d\rho\,d\phi\,d\theta
     \]

   - **Option (c):**
     \[
     \int_0^{2\pi} \int_0^{\pi/4} \int_0^{4\sec\theta} \rho^2 \sin\phi\,d\rho\,d\phi\,d\theta
     \]

These integrals are used to calculate the volumes based on the specific geometrical constraints and limits provided in the integrals.
Transcribed Image Text:**The Volume of Geometric Shapes Using Integration** 1. **Volume of the Right Circular Cylinder** To find the volume of a right circular cylinder with a base of radius 4 in the xy-plane and height 5, evaluate the following integrals: - **Option (a):** \[ \int_0^5 \int_0^{2\pi} \int_0^4 dr\,d\theta\,dz \] - **Option (b):** \[ \int_0^5 \int_0^{2\pi} r\,dr\,d\theta\,dz \] - **Option (c):** \[ \int_0^5 \int_0^{2\pi} \int_0^2 dr\,d\theta\,dz \] 2. **Volume Inside the Cone \(\phi = \pi/4\), \(0 \leq z \leq 4\)** To find the volume of the region inside the cone where \(\phi = \pi/4\) and \(0 \leq z \leq 4\), evaluate these integrals: - **Option (a):** \[ \int_0^{2\pi} \int_0^{\pi/4} \int_0^{4\sqrt{2}} \rho\,d\rho\,d\phi\,d\theta \] - **Option (b):** \[ \int_0^{2\pi} \int_0^{\pi/4} \int_0^4 \rho^2 \sin\phi\,d\rho\,d\phi\,d\theta \] - **Option (c):** \[ \int_0^{2\pi} \int_0^{\pi/4} \int_0^{4\sec\theta} \rho^2 \sin\phi\,d\rho\,d\phi\,d\theta \] These integrals are used to calculate the volumes based on the specific geometrical constraints and limits provided in the integrals.
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