The volume of the right circular cylinder with a base of radius 4 in the ry-plane and height 5 is 5 27 c4 (a) I drdedz. (b) rdrdodz . drdOdz . Jo Jo The volume of the region inside the cone o = t/4 for 0
The volume of the right circular cylinder with a base of radius 4 in the ry-plane and height 5 is 5 27 c4 (a) I drdedz. (b) rdrdodz . drdOdz . Jo Jo The volume of the region inside the cone o = t/4 for 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Concept explainers
Cylinders
A cylinder is a three-dimensional solid shape with two parallel and congruent circular bases, joined by a curved surface at a fixed distance. A cylinder has an infinite curvilinear surface.
Cones
A cone is a three-dimensional solid shape having a flat base and a pointed edge at the top. The flat base of the cone tapers smoothly to form the pointed edge known as the apex. The flat base of the cone can either be circular or elliptical. A cone is drawn by joining the apex to all points on the base, using segments, lines, or half-lines, provided that the apex and the base both are in different planes.
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![**The Volume of Geometric Shapes Using Integration**
1. **Volume of the Right Circular Cylinder**
To find the volume of a right circular cylinder with a base of radius 4 in the xy-plane and height 5, evaluate the following integrals:
- **Option (a):**
\[
\int_0^5 \int_0^{2\pi} \int_0^4 dr\,d\theta\,dz
\]
- **Option (b):**
\[
\int_0^5 \int_0^{2\pi} r\,dr\,d\theta\,dz
\]
- **Option (c):**
\[
\int_0^5 \int_0^{2\pi} \int_0^2 dr\,d\theta\,dz
\]
2. **Volume Inside the Cone \(\phi = \pi/4\), \(0 \leq z \leq 4\)**
To find the volume of the region inside the cone where \(\phi = \pi/4\) and \(0 \leq z \leq 4\), evaluate these integrals:
- **Option (a):**
\[
\int_0^{2\pi} \int_0^{\pi/4} \int_0^{4\sqrt{2}} \rho\,d\rho\,d\phi\,d\theta
\]
- **Option (b):**
\[
\int_0^{2\pi} \int_0^{\pi/4} \int_0^4 \rho^2 \sin\phi\,d\rho\,d\phi\,d\theta
\]
- **Option (c):**
\[
\int_0^{2\pi} \int_0^{\pi/4} \int_0^{4\sec\theta} \rho^2 \sin\phi\,d\rho\,d\phi\,d\theta
\]
These integrals are used to calculate the volumes based on the specific geometrical constraints and limits provided in the integrals.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F25fb0993-5d26-4149-a829-39bf7f0bd1d0%2Fc76e05cb-9c1a-4ec8-9567-d14c43ab7418%2F8f0srz_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**The Volume of Geometric Shapes Using Integration**
1. **Volume of the Right Circular Cylinder**
To find the volume of a right circular cylinder with a base of radius 4 in the xy-plane and height 5, evaluate the following integrals:
- **Option (a):**
\[
\int_0^5 \int_0^{2\pi} \int_0^4 dr\,d\theta\,dz
\]
- **Option (b):**
\[
\int_0^5 \int_0^{2\pi} r\,dr\,d\theta\,dz
\]
- **Option (c):**
\[
\int_0^5 \int_0^{2\pi} \int_0^2 dr\,d\theta\,dz
\]
2. **Volume Inside the Cone \(\phi = \pi/4\), \(0 \leq z \leq 4\)**
To find the volume of the region inside the cone where \(\phi = \pi/4\) and \(0 \leq z \leq 4\), evaluate these integrals:
- **Option (a):**
\[
\int_0^{2\pi} \int_0^{\pi/4} \int_0^{4\sqrt{2}} \rho\,d\rho\,d\phi\,d\theta
\]
- **Option (b):**
\[
\int_0^{2\pi} \int_0^{\pi/4} \int_0^4 \rho^2 \sin\phi\,d\rho\,d\phi\,d\theta
\]
- **Option (c):**
\[
\int_0^{2\pi} \int_0^{\pi/4} \int_0^{4\sec\theta} \rho^2 \sin\phi\,d\rho\,d\phi\,d\theta
\]
These integrals are used to calculate the volumes based on the specific geometrical constraints and limits provided in the integrals.
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