The volume of a sphere is increasing at a constant rate of 1827 cubic centimeters per second. At the instant when the radius of the sphere is 4 centimeters, what is the rate of change of the surface area of the sphere? The volume of a sphere can be found with the equation V = ³ and the surface 1 πρ area can be found with S = 4πr². Round your answer to three decimal places (if necessary).

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