The volume of a right-circular cone is V=²h, where r is the radius of the base and he is the height of the cone. Let's assume all the length units are in microns (m). Furthermore, it turns out that this right-circular cone is describing a special kind of cancerous tumour, which is growing: The base radius r is growing at a rate of 6 μm/second while the height h is growing at a rate of 6 μm/second. Find the rate of increase in volume (in μm³/second) when r-16 μm and h-9 μm. [Answer should be correct upto second decimal place] Number

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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The volume of a right-circular cone is V = =²¹h, where r is the radius of the base and h is the height of the cone. Let's assume all the length units are in
3
microns (m). Furthermore, it turns out that this right-circular cone is describing a special kind of cancerous tumour, which is growing: The base radius r is
growing at a rate of 6 μm/second while the height h is growing at a rate of 6 m/second. Find the rate of increase in volume (in
3
μm/second) when r-16 um and h-9 um. [Answer should be correct upto second decimal place]
Number
Transcribed Image Text:The volume of a right-circular cone is V = =²¹h, where r is the radius of the base and h is the height of the cone. Let's assume all the length units are in 3 microns (m). Furthermore, it turns out that this right-circular cone is describing a special kind of cancerous tumour, which is growing: The base radius r is growing at a rate of 6 μm/second while the height h is growing at a rate of 6 m/second. Find the rate of increase in volume (in 3 μm/second) when r-16 um and h-9 um. [Answer should be correct upto second decimal place] Number
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