The volume enclosed by the plates of a parallel plate capacitor is given by the equation Volume = Ad. If one doubles the area, A, of the plates and reduces the plate separation, d, by a factor of two so that the volume remains the same, the capacitance will do which of the following? decrease by a factor of 4 increase by a factor of 4 increase by a factor of 2 decrease by a factor of 2 remain constant
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An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
SOlution:
given that
in the capacitor the area made double and distance reduce to half, what is the effect of this on the capacitance
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